Advanced Organic Chemistry: Mass spectrum of propanamide CH3CH2CONH2

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Interpreting the mass spectrum of propanamide (propionamide)

[Author © Dr Phil Brown PhD: Doc Brown's advanced level organic chemistry exam revision notes suitable for students of UK A level chemistry courses & US K12 grade 11, grade 12 and AP honors chemistry courses: Molecular spectroscopy analysis of propanamide [spectra page updated Mar 26th 2026 *]

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 Mass spectrometry - spectra index


Introductory note on the mass spectrum of propanamide

Students and teachers please note my explanation of the mass spectrum of propanamide is designed for advanced, but pre-university, chemistry courses.

If M represents the propanamide molecule, the initial ionisation to give the molecular ion is:

M(g) + high KE e-  ==> [M]+(g) + 2e- and for fragmentation equations assume [M]+ is the start of the processes and all species are in a gaseous state.

I've not usually shown an unpaired electron on e.g. an ion or a non-ionised alkyl radical R e.g.

[M]+ ==> [X]+  +  R, but you should be aware this is a more accurate depiction of some processes.

I've used simplified equations to show how some of the ions that might be formed in the fragmentation pattern for the mass spectrum of propanamide and only the formation of singly charged positive are considered for the mass spectrum of propanamide.

I've included a stick diagram and table of m/z ions for the mass spectrum of propanamide and doing the mass spectrum analysis under standard conditions, databases can be compiled based on complex fingerprint patterns, often involving the relative intensities of many fragment ions, and used to identify compounds including propanamide.

In selected cases, where two different fragment ions have the same integer m/z value, I've pointed out that modern mass spectrometers can measure relative ion mass to four decimal places. So, using accurate isotopic masses, I've calculated the accurate ion masses, BUT strictly speaking, 0.0005 should be deducted for singly charged ions to account for the loss of the electron in their formation. I have NOT done this for propanamide, but the mass spectrometer software does!

mass spectrum of propanamide fragmentation pattern of m/z m/e ions for analysis and identification of propanamide image diagram doc brown's advanced organic chemistry revision notes 

propanamide (propionamide), C3H7NO, (c) doc b, (c) doc b, (c) doc b

The molecular structure and naming of carboxylic acids and derivatives

The classification, structure and naming of organic nitrogen compounds

Interpreting the fragmentation pattern of the mass spectrum of propanamide

[M]+ is the molecular ion peak (M) with an m/z of 73 corresponding to [C3H7NO]+, the original propanamide molecule minus an electron, [CH3CH2CONH2]+

The small M+1 peak at m/z 74, corresponds to an ionised propanamide molecule with one 13C atom in it i.e. an ionised propanamide molecule of formula 13C12C2H7NO

Carbon-13 only accounts for ~1% of all carbon atoms (12C ~99%), but the more carbon atoms in the molecule, the greater the probability of observing this 13C M+1 peak.

Propanamide has 3 carbon atoms, so on average, ~1 in 33 molecules will contain a 13C atom.

The most abundant ion of the molecule under mass spectrometry investigation (propanamide) is usually given an arbitrary abundance value of 100, called the base ion peak, and all other abundances ('intensities') are measured against it.

The base ion peak for the mass spectrum of propanamide is the m/z 44 ion [O=C-NH2]+

Identifying the species giving the most prominent peaks (apart from M) in the fragmentation pattern of propanamide.

Parent molecular ion for propanamide is the m/z 59 ion  to [C3H7NO]+ or [CH3CH2CONH2]+

m/z value of [fragment]+ 72 57 55 ? 54 45 44
[molecular fragment]+ [C3H6NO]+ [CH3CH2C=O]+ [C3H3O]+ or [C3H5N]+ [C3H4N]+ [C2H5O]+ or [CH3NO]+ [O=C-NH2]+
m/z value of [fragment]+ 30 29 28 [C2H4]+ 27 26 18 15
[molecular fragment]+ CH4N [CH3CH2]+ [CH2=CH2]+ [C2H3]+ [C2H3]+ [?]+ [CH3]+

Analysing and explaining the principal ions in the fragmentation pattern of the mass spectrum of propanamide (finger print pattern of ions and their abundances)

PLEASE NOTE I have found it difficult to find 'authentic' equations to explain mass spectra fragmentation patterns and it is complex chemistry! I've identified the formulae of the ionised fragments on the mass spectrum diagram, but the equations are from the internet or my conjecture as to how the ions might be formed - please take care in using the information, especially for assignments at university or pre-university level.

Possible suggested equations to explain the most abundant ion peaks of the propanamide mass spectrum

There are many fragments and lots of possible fragmentation process, some are more favoured than others, but this becomes university level analysis!

Formation of m/z 72 ion

[CH3CH2CONH2]+  ===>  [C3H6NO]+  +  H

C-H or N-H bond scission in parent molecular ion, proton loss.

mass change 73 - 11 = 72 (M-16 ion peak)

Formation of m/z 57 ion

[CH3CH2CONH2]+  ===>  [CH3CH2C=O]+  +  NH2

C-N bond scission in parent molecular ion, loss of NH2 group

mass change 73 - 16 = 57 (M-16 ion peak)

Formation of m/z 55 ion

(i) [?]+  ===>  [C3H3O]+  +  ?

or more likely?

(ii) [?]+  ===>  [C3H5N]+  +  ?

I'm not sure which fragment species predominates for these pairs with the same m/z integer value, which I'm sure can be formed by other fragmentation reactions, BUT an accurate mass spectrometer can sort them out - can measure relative fragment ion masses to four decimal places e.g. using accurate relative isotopic masses:

1H = 1.0078    12C = 12.0000    14N = 14.0031   16O = 15.9949

Accurate relative ion masses: [C3H3O]+ = 55.0183  and [C3H5N]+ = 55.0421, difference of 0.0238 in ion relative mass can be easily resolved.

Formation of m/z 44 and 45 ions

[CH3CH2CONH2]+  ===>  [O=C-NH2]+  +  CH3CH2

C-C bond scission in the parent molecular ion, loss of ethyl group.

mass change = 73 - 29 = 44 (M-29 ion peak), [CH2NO]+ (see below)

The m/z 44 ion is the base peak ion, the most abundant 'stable' ion fragment.

m/z 45 ion could be the related [13CH2NO]+ formed in the same way or less likely the  [C2H5O]+ ion.

Again, using accurate relative isotopic masses:

1H = 1.0078  12C = 12.0000   13C = 13.0034   14N = 14.0031   16O = 15.9949: you can then calculate (predict) that the accurate relative ion masses are:

For m/z 45: [C2H5O]+ = 45.0339 and [13CH2NO]+ = 45.0170, a relative ion mass difference of 0.01690 with C2H5O

Formation of m/z 26 to 29 ions

[CH3CH2CONH2]+  ===>  [CH3CH2]+  +  CONH2

C-C bond scission in the parent molecular ion, loss of CONH2 group.

mass change = 73 - 44 = 29 (M-44 ion peak)

This m/z 29 ion can lose protons to generate the m/z 28, 27 and 26 ions.

The m/z 28 ion can be formed by elimination of ethene from a larger fragment of >= 2 carbon atoms and, similarly, the m/z 26 ion by the elimination of ethyne.

Formation of m/z 15 ion

[any of above m/z ions 29, 57, 72 or 73]+  ===>  [CH3]+  +  neutral residue i.e. C-C bond scission of any ion with a CH3 group.


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