isomers of molecular formula C5H11F, C5H11Cl, C5H11Br and C5H11I

Advanced organic chemistry: Structural isomers of molecular formula C5H11F, C5H11Cl, C5H11Br, C5H11I

Doc Brown's Advanced Chemistry: Part 14.7

The constitutional-structural isomers of molecular formula C5H11F, C5H11Cl, C5H11Br and C5H11I

[Author ©  Dr Phil Brown GRIC, PhD: Doc Brown's advanced level organic chemistry exam revision notes suitable for students of UK advanced level chemistry courses, IB advanced chemistry & US K12 grades 11-12 and AP honors chemistry courses: Molecular spectroscopy and analysing the isomers of C5H11X (X = halogen) [page updated RE-EDIT]


Sub-index for this page on the isomers of  C5H11X (X = halogen)

(a) Introduction to the 8 constitutional-structural isomers of formula C5H11X

(b) Details of the 8 constitutional isomers of molecules of formulae C5H11X

(c) EXTRA NOTES constitutional isomers of molecules of C5H11X (X = halogen)

(d) Learning objectives - questions to be answered?

(e) Practise exam questions based on isomers of C5H11X (X = halogen)


 Associated organic chemistry page links

 Index of sets of isomers for a given molecular formula

 This is a big chemistry website, please allow time to explore it

 email doc brown - comments - query? * [privacy policy, cookies and disclaimer]


(a) Introduction to the 8 constitutional-structural isomers for each molecular formula C5H11F, C5H11Cl, C5H11Br or C5H11I

isomers of C5H11Cl C5H11Br C5H11I  C5H11F skeletal formula types of isomerism how to analysise C5H11Cl C5H11Br C5H11I  C5H11F for R/S optical positional isomers of C5H11Cl C5H11Br C5H11I  C5H11F 

Relative molecular mass and percent composition of C5H11X (X = halogen) based on atomic masses:

C 12.01H 1.01, F 19.00Cl 35.45 Br 79.90, I 126.90

Formula of compound Relative molecular mass % carbon % hydrogen % halogen
C5H11F 90.16 66.61 12.32 21.07
C5H11Cl 106.61 56.33 10.42 33.25
C5H11Br 151.06 39.75 7.36 52.89
C5H11I 198.06 30.32 5.61 64.07

Empirical formula = molecular formula = C5H11X (where X = a single halogen atom)

If applicable (see isomerism summary at the end of the page)

Structural isomerism  - isomers of the same specific molecular formula, based on different connectivity's of the constituent atoms (the constitutional isomers), so they cannot be spatially identical (but sometimes can be defined as having the same shape).

This includes (a) carbon chain variation (usually need a minimum of 4 atoms), (b) change in position of a substituent or functional group and (c) functional group isomerism where the atoms have a different connectivity configuration, usually with significant differences in chemical and physical properties e.g.

The isomers here are based on (a) carbon chain variation and (b) halogen atom position.

You might consider the terms primary, secondary and tertiary as minor functional group isomerism?

Stereoisomerism - isomers based on the same connectivity of the atoms (same constitutional formula), but in some way, they are 2D or 3D spatially different non-superimposable images (e.g. E/Z 'geometrical' isomers or mirror image R/S 'optical' isomers)

E/Z stereoisomerism was called 'geometrical isomerism' e.g. cis (= Z) and trans (= E) isomers of alkenes or disubstituted cyclic alkanes where there are 2D/3D spatial variations that are not mirror images and not super imposable.

This is not possible for these open chain saturated aliphatic compounds.

e.g. because there is no >C=C< double bond in these molecules/

R/S stereoisomerism was called 'optical isomerism', the pairs of isomers are called enantiomers, which are 3D non-superimposable mirror image forms of the molecule (enantiomers).

The molecule must have a chiral centre (a stereocentre), that is an asymmetric carbon atom with four different atoms/groups attached to it.

There are several R/S optical isomers.

NOTE

Some of the isomers described may be highly reactive and very thermodynamically unstable e.g. due to weak highly strained bonds and some may not even exist at all (except theoretically of course!).

The images of C5H11X (X = F, Cl, Br and I) presented are theoretical, in the sense that some may be so unstable as not to exist, but I think you will find all of them, on the internet.

The are only 8 constitutional-structural isomers of molecular formula C5H11X (X = F, Cl, Br and I), irrespective of any E/Z or R/S isomerism that may be possible.

They are all saturated open chain aliphatic compounds derived from halogen mono-substitution products of alkane hydrocarbons with the formula C5H12

Since three of the constitutional structural isomers exhibit R/S isomerism, there are a total of 11 different distinct isomers for each C5H11X formula.


(b) Details of the 8 constitutional isomers of molecules of formulae C5H11F, C5H11Cl, C5H11Br and C5H11I (includes stereoisomers and brief notes on 1H NMR and 13C NMR spectra data)

and any possible stereoisomers, which happen to be all R/S 'optical' isomers.

They are all saturated mono-substituted products of alkanes i.e. they are all monosubstituted haloalkane.

 

(1) CH3CH2CH2CH2CH2X, abbreviated structural formula, skeletal formula of 1-fluoropentane, 1-chloropentane, 1-bromopentane, 1-iodopentane, isomers of C5H11Cl, C5H11Br, C5H11I, C5H11F , skeletal formula

1-fluoropentane, 1-chloropentane, 1-bromopentane, 1-iodopentane

Primary haloalkanes (primary halogenoalkanes)

e.g. (c) doc b , structural formula 1-chloropentane , skeletal formula 1-chloropentane

Number of low resolution NMR chemical shift δ signal peaks: 5 1H and 5 13C (email if disagree?)

1H NMR ratio of peaks: 3 : 2 : 2 : 2 : 2 (for equivalent protons)

Index of 1H NMR spectra organic compounds and Index of 13C NMR spectra organic compounds

 

(2) CH3CH2CH2CHXCH3, abbreviated structural formula, skeletal formula of 2-fluoropentane, 2-chloropentane, 2-bromopentane, 2-iodopentane, R/S optical isomers of C5H11Cl, C5H11Br, C5H11I, C5H11F , skeletal formula

2-fluoropentane, 2-chloropentane, 2-bromopentane, 2-iodopentane

Secondary haloalkanes (secondary halogenoalkanes)

Can form R/S isomers, 2nd carbon atom is chiral.

CIP assignment priority rule for R/S isomers:

ZX  >  6C6C  > 6C1H  >  1H (X = halogen, Z = 9, 17, 35, 53)

e.g. (c) doc b , structural formula 2-chloropentane , skeletal formula 2-chloropentane

Number of low resolution NMR chemical shift δ signal peaks: 5 1H and 5 13C (email if disagree?)

1H NMR ratio of peaks: 3 : 2 : 2 : 1 : 3 (for equivalent protons)

 

(3) CH3CH2CHXCH2CH3, abbreviated structural formula, skeletal formula of 3-fluoropentane, 3-chloropentane, 3-bromopentane, 3-iodopentane, isomers of C5H11Cl, C5H11Br, C5H11I, C5H11F , skeletal formula

3-fluoropentane, 3-chloropentane, 3-bromopentane, 3-iodopentane

Secondary haloalkanes (secondary halogenoalkanes)

e.g. (c) doc b , structural formula 3-chloropentane , skeletal formula 3-chloropentane

Number of low resolution NMR chemical shift δ signal peaks: 3 1H and 3 13C (email if disagree?)

1H NMR ratio of peaks: 6 (3+3) : 4 (2+2) : 1 (for equivalent protons)

 

(4) CH3CH2CH(CH3)CH2X, abbreviated structural formula, skeletal formula of 1-fluoro-2-methylbutane, 1-chloro-2-methylbutane, 1-bromo-2-methylbutane, 1-iodo-2-methylbutane, R/S optical isomers of C5H11Cl, C5H11Br, C5H11I, C5H11F , skeletal formula

1-fluoro-2-methylbutane, 1-chloro-2-methylbutane, 1-bromo-2-methylbutane, 1-iodo-2-methylbutane

Primary haloalkanes (primary halogenoalkanes)

Can form R/S isomers, 2nd carbon atom is chiral.

CIP assignment priority rule for R/S isomers:

6CZX  >  6C6  >  6C1H  >  1H (X = halogen, Z = 9, 17, 35, 53)

e.g. (c) doc b , structural formula 1-chloro-2-methylbutane , skeletal formula 1-chloro-2-methylbutane

Number of low resolution NMR chemical shift δ signal peaks: 5 1H and 5 13C (email if disagree?)

1H NMR ratio of peaks: 3 : 2 : 1 : 3 : 2 (for equivalent protons)

 

(5) (CH3)2CHCH2CH2X, abbreviated structural formula, skeletal formula of 1-fluoro-3-methylbutane, 1-chloro-3-methylbutane, 1-bromo-3-methylbutane, 1-iodo-3-methylbutane, isomers of C5H11Cl, C5H11Br, C5H11I, C5H11F , skeletal formula

1-fluoro-3-methylbutane, 1-chloro-3-methylbutane, 1-bromo-3-methylbutane, 1-iodo-3-methylbutane

Primary haloalkanes (primary halogenoalkanes)

Number of low resolution NMR chemical shift δ signal peaks: 4 1H and 4 13C (email if disagree?)

1H NMR ratio of peaks: 6 (3+3) : 1 : 2 : 2 (for equivalent protons)

 

(6) CH3CH2CX(CH3)2, abbreviated structural formula, skeletal formula of 2-fluoro-2-methylbutane, 2-chloro-2-methylbutane, 2-bromo-2-methylbutane, 2-iodo-2-methylbutane, isomers of C5H11Cl, C5H11Br, C5H11I, C5H11F , skeletal formula

2-fluoro-2-methylbutane, 2-chloro-2-methylbutane, 2-bromo-2-methylbutane, 2-iodo-2-methylbutane

Tertiary haloalkanes (tertiary halogenoalkanes)

e.g. (c) doc b , structural formula 2-chloro-2-methylbutane , skeletal formula 2-chloro-2-methylbutane

Number of low resolution NMR chemical shift δ signal peaks: 3 1H and 4 13C (email if disagree?)

1H NMR ratio of peaks: 3 : 2 : 6 (3+3) (for equivalent protons)

 

(7) (CH3)2CHCHXCH3, abbreviated structural formula, skeletal formula of 2-fluoro-2-methylbutane, 2-chloro-3-methylbutane, 2-bromo-3-methylbutane, 2-iodo-3-methylbutane, R/S optical isomers of C5H11Cl, C5H11Br, C5H11I, C5H11F , skeletal formula

2-fluoro-3-methylbutane, 2-chloro-3-methylbutane, 2-bromo-3-methylbutane, 2-iodo-3-methylbutane

Secondary haloalkanes (secondary halogenoalkanes)

Can form R/S isomers, 2nd carbon atom is chiral.

CIP assignment priority rule for R/S isomers:

ZX  >  6C6C  >  6C1H  >  1H (X = halogen, Z = 9, 17, 35, 53)

e.g. (c) doc b , structural formula 2-chloro-3-methylbutane , skeletal formula 2-chloro-3-methylbutane

Number of low resolution NMR chemical shift δ signal peaks: 4 1H and 4 13C (email if disagree?)

1H NMR ratio of peaks: 6 (3+3) : 1 : 1 : 3 (for equivalent protons)

 

(8) (CH3)3CCH2X, abbreviated structural formula, skeletal formula of 1-fluoro-2,2-dimethylpropane, 1-chloro-2,2-dimethylpropane, 1-bromo-2,2-dimethylpropane, 1-iodo-2,2-dimethylpropane, isomers of C5H11Cl, C5H11Br, C5H11I, C5H11F , skeletal formula

1-fluoro-2,2-dimethylpropane, 1-chloro-2,2-dimethylpropane, 1-bromo-2,2-dimethylpropane, 1-iodo-2,2-dimethylpropane

Primary haloalkanes (primary halogenoalkanes)

e.g. (c) doc b , structural formula 1-chloro-2,2-dimethylpropane , skeletal formula 1-chloro-2,2-dimethylpropane

Number of low resolution NMR chemical shift δ signal peaks: 2 1H and 3 13C (email if disagree?)

1H NMR ratio of peaks: 9(3x3) : 2 (for equivalent protons)


(c) EXTRA NOTES constitutional isomers of molecules of C5H11X (X = halogen)

Number of constitutional isomers (monohalo‑pentanes)

All monosubstituted halopentanes (C5H11F, C5H11Cl, C5H11Br and C5H11I) have the same set of constitutional isomers: eight distinct structural isomers in total.

These arise from placing one halogen atom on every non‑equivalent carbon of the three inequivalent C5 skeletons (n‑pentane, 2‑methylbutane, 2,2‑dimethylpropane) and accounting for symmetry.

Summary list and description of the eight constitutional isomers (how they differ)

  1. 1‑halopentane (halogen on terminal carbon of n‑pentane) — primary, unbranched.

  2. 2‑halopentane (halogen on C‑2 of n‑pentane) — secondary, unbranched; chiral centre when Hs differ.

  3. 3‑halopentane (halogen on C‑3 of n‑pentane) — secondary, unbranched; centrally placed.

  4. 1‑halomethylbutane (halogen on terminal of 2‑methylbutane, commonly named 1‑halopentane isomer variant) — primary on a branched chain.

  5. 2‑halomethylbutane (halogen on C‑2 of 2‑methylbutane) — secondary, branched; can be stereogenic.

  6. 3‑halomethylbutane (halogen on C‑3 of 2‑methylbutane) — secondary/primary depending on numbering convention; non‑equivalent to other positions.

  7. 1‑haloneopentyl (halogen on a terminal carbon of the neopentyl skeleton) — primary but highly hindered (neopentyl).

  8. 2‑haloneopentyl (halogen on the quaternary‑adjacent carbon is impossible; the only unique halogen position on 2,2‑dimethylpropyl gives the neopentyl isomer set above) — practical enumeration yields eight unique structures in total when symmetry is removed.

Types of isomerism exhibited and explanation

  • Structural (constitutional) isomerism: different connectivity of C and X (position of halogen and branching) — the primary class for these formulas.

  • Positional isomerism: same carbon skeleton but halogen on different carbon atoms (1‑, 2‑, 3‑ positions).

  • Chain (skeletal) isomerism: straight chain versus branched chains (n‑pentane, 2‑methylbutane, 2,2‑dimethylpropane).

  • Stereoisomerism (where relevant): some secondary halides create chiral centres (e.g., 2‑halopentane) and therefore enantiomers; diastereomers are possible only where more than one stereogenic element exists (rare here for monosubstituted species).

Differences in physical properties (linked to structure and halogen)

  • Boiling point: increases with halogen polarizability/size (F < Cl < Br < I) for the same constitutional isomer because of larger London dispersion forces for heavier halogens. Branching lowers boiling point for a given halogen due to reduced surface area.

  • Density: increases with heavier halogen (iodides densest).

  • Polarity and dipole moment: depends on halogen electronegativity and substitution position; 1‑halides often have different molecular dipoles than internal halides (2‑ or 3‑).

  • Volatility & vapour pressure: branched isomers are generally more volatile than straight‑chain isomers; fluorides tend to be less polarizable and therefore lower boiling than heavier halides for comparable connectivity.

Differences in chemical reactions and relative reactivity

  • Nucleophilic substitution (SN1/SN2): reactivity order for leaving group ability is I > Br > Cl >> F; iodides and bromides undergo SN2 or SN1 more readily under comparable conditions, fluorides are poorest leaving groups and often require special conditions. Secondary halides (e.g., 2‑halopentane) can undergo both SN1 and SN2 depending on solvent and nucleophile; primary halides favour SN2; tertiary (not present here) favour SN1.

  • Elimination (E2/E1): secondary halides are more prone to elimination under strong base/heat than primary halides. Vicinal H availability and steric hindrance influence elimination rates.

  • Radical reactions (homolytic cleavage/halogen exchange): C–X bond strength decreases down the group (C–F strongest, C–I weakest), so radical cleavage and radical substitution are easier for bromides/iodides.

  • Organometallic formation: iodides and bromides are readily converted to Grignard or organolithium reagents (or by halogen–metal exchange), chlorides less so, fluorides rarely directly.

  • Chemoselectivity and steric effects: neopentyl halides (sterically hindered primary halides) are unusually unreactive in SN2 despite being primary because steric hindrance blocks backside attack.

Uses and applications linked to isomer structure and halogen identity

  • For C5H11F, C5H11Cl, C5H11Br and C5H11I

  • Fluorides: used in specialty organofluorine chemistry, medicinal chemistry leads (modifying metabolic stability and lipophilicity), and where strong C–F bond confers stability. Less useful as leaving groups or direct synthetic handles.

  • Chlorides: common as chemical intermediates, solvents or feedstocks; used where moderate stability and moderate reactivity are required.

  • Bromides: widely used as synthetic electrophiles for substitution, radical chemistry, and preparation of organometallic reagents; preferred for many laboratory transformations.

  • Iodides: highly reactive electrophiles and excellent substrates for rapid substitution, halogen–metal exchange and radiolabelling; often used when high reactivity is required in synthesis.

  • Structural isomer application notes: primary linear halides often serve as good SN2 substrates (except bulky neopentyl); secondary internal halides are chosen when SN1 or elimination is desired; branched isomers are chosen when steric stabilization or lower volatility is required.

Student misconceptions to highlight and exam tips

  • “All primary halides react fastest in all substitutions” — false: neopentyl primary halides are poor SN2 substrates due to steric hindrance.

  • “Fluorides behave like other halides in substitution” — false: fluoride is a very poor leaving group in protic conditions and C–F bonds are exceptionally strong.

  • “Leaving‑group ability equals nucleophilicity” — false: nucleophilicity and leaving‑group ability are related but not identical properties and depend on solvent and base/nucleophile.

  • “All isomers have identical boiling points because formula is same” — false: branching, position of halogen and halogen identity strongly affect boiling point and density.

  • Learn the three backbone types for C5 and systematically place the halogen at non‑equivalent positions to generate the eight isomers; practise drawing them quickly and naming them IUPAC correctly.

  • Memorise the leaving‑group trend I > Br > Cl >> F and link it to bond strength and polarizability in exam answers.

  • Use structural features to predict mechanism: primary → SN2 likely; secondary → SN1 or SN2 depending on conditions; discuss steric hindrance explicitly for neopentyl cases.

  • In comparative questions mention both physical (bpt, density, polarity) and chemical (reactivity, mechanism preference) differences and link each point to a structural reason.

  • For stereochemistry questions identify possible chiral centres (e.g., 2‑halopentane) and state whether enantiomers exist. Draw quick wedge/dash sketches when asked.

  • Practice short explanation answers: e.g., “2‑bromopentane is more reactive than 1‑bromopentane in SN1 because the secondary carbocation is more stable” — then add a one‑line structural justification.


(d) Learning objectives - questions to be answered?

Can you IUPAC name these isomers?

Can you deduce the number of principal 1H chemical shifts and proton ratio you would expect to see in the NMR spectrum of these isomers?

Can you deduce the number of principal 13C chemical shifts you would expect to see in the NMR spectrum of these isomers?

How do you draw the structural formula and skeletal formula of the isomers of molecular formula C5H11F C5H11Cl C5H11Br C5H11I?

How many aliphatic structural isomers are there of halogen compounds with molecular formula C5H11F C5H11Cl C5H11Br C5H11I?

How many aliphatic carbon chain isomers are there of halogen compounds with molecular formula C5H11F C5H11Cl C5H11Br C5H11I?

How many positional isomers are there of organic halogen molecules with molecular formula C5H11F C5H11Cl C5H11Br C5H11I?

How many E/Z (geometrical) isomers are there of molecular formula C5H11F C5H11Cl C5H11Br C5H11I?

How many R/S (optical) isomers (enantiomers) of molecular formula C5H11F C5H11Cl C5H11Br C5H11I?

Are there any halocycloalkene isomers of formula C5H11F C5H11Cl C5H11Br C5H11I?

Are there any cyclic haloalkene isomers of formula C5H11F C5H11Cl C5H11Br C5H11I?

Are there any cyclo haloalkane isomers of formula C5H11F C5H11Cl C5H11Br C5H11I?

Are there any halodiene isomers of molecular formula C5H11F C5H11Cl C5H11Br C5H11I?

Are there any haloalkyne isomers of molecular formula C5H11F C5H11Cl C5H11Br C5H11I?

Are there any functional group isomers with a molecular formula C5H11F C5H11Cl C5H11Br C5H11I?

Do C5H11F C5H11Cl C5H11Br C5H11I organic halogen molecules have any stereoisomers?

Are there any E/Z (geometrical) isomers with a molecular formula C5H11F C5H11Cl C5H11Br C5H11I?

Are there any R/S (optical) isomers (enantiomers) with a molecular formula C5H11F C5H11Cl C5H11Br C5H11I?

This page will answer these questions for molecular formula C5H11F C5H11Cl C5H11Br C5H11I


(e) QUESTIONS

Practise exam questions based on isomers of molecular formula the isomers of C5H11X (X = halogen)

Jot down your responses and check out the answers

 ANSWERS to the questions based on the isomers of C5H11X (X = halogen)

If you think there are any errors, please email me asap at chem55555@hotmail.com

I don't mind if students/teachers do a selected printout of these questions and answers.


You are given four pairs of haloalkane isomers, answer the questions with as much reasoning as possible.

Q1 Name A to H with IUPAC names and give their classification as primary (prim), secondary (sec) or tertiary (tert).


Q2 (a) Which will on hydrolysis aqueous sodium hydroxide, will yield a secondary alcohol?

(b) Write a skeletal formula equation for one of the hydrolysis reactions and state the name of the product and what type of mechanism pathway the reaction will take.

(c) Explain which of them is likely to react the fastest and which the slowest irrespective of the mechanistic pathway the hydrolysis takes.

(d) Which is the only one to yield a tertiary alcohol on hydrolysis


Q3 Which of the molecules will form a pair of R/S ('optical') isomers? and quote their chiral centre.


Q4 Which of C and F would react the fastest on refluxing with aqueous sodium hydroxide?


Q5 Which of E and H would react the fastest on refluxing with aqueous sodium hydroxide?


If you think there are any errors, please email me asap at chem55555@hotmail.com

I don't mind if students/teachers do a selected printout of these questions and answers.


Associated organic chemistry  links

Index of sets of isomers for a given molecular formula

The molecular structure and naming of HALOALKANES (how to name and draw alkane structures)

The molecular structure and naming of ALKANES (how to name and draw alkane structures)

The molecular structure and naming of ALKENES (how to name and draw alkene structures)

Index of revision notes on the chemistry HALOALKANES including reactions

Index of revision notes on the chemistry of ALKANES and the petrochemical industry

Index of revision notes on the chemistry ALKENES including reactions and polymers

 Advanced Level pre-university organic chemistry notes

 IR, mass and H-1 and C-13 NMR spectra of organic compounds

For isomerism in organic chemistry, see also the notes

Isomerism: introduction, structural isomerism - chain, positional, functional group, tautomerism

Stereoisomerism: introduction, definition, priority rules, E/Z isomerism (cis/trans isomerism)

 Stereoisomerism - R/S isomerism (optical isomerism) - definition - examples explained

 This is a big chemistry website, please allow time to explore it

Index of my advanced (pre-college/university) organic chemistry revision notes

 Index of all my spectroscopy pages

 Index of all my isomerism pages

 The chemistry of alkanes and the petrochemical industry

 The chemistry of alkenes

 The chemistry of haloalkanes

 The chemistry of alcohols

 The chemistry of aldehydes and ketones

 The chemistry of carboxylic acids and derivatives

 The chemistry of organo-nitrogen compounds

 The chemistry of aromatic compounds


A summary chart of isomerism

index for all isomerism pages

Website content © Dr Phil Brown 2000+. All copyrights reserved on Doc Brown's Chemistry revision notes, images, quizzes, worksheets etc. Copying of website material is NOT permitted. Advanced level pre-university/college organic chemistry revision notes  The isomerism of molecular formulae C5H11F, C5H11Cl, C5H11Br and C5H11I. All suitable for chemistry students taking the WJEC advanced A level chemistry, CCEA advanced A level chemistry, Cambridge CIE advanced A level chemistry, AQA advanced A level chemistry, Edexcel advanced A level chemistry, OCR advanced A level chemistry, Salters advanced A level chemistry, IB advanced level chemistry, US grade 11-12 K12 AP Honors chemistry courses

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ANSWERS to the practise exam questions based on isomers of molecular formula the isomers of C5H11X (X = halogen)

If you think there are any errors, please email me asap at chem55555@hotmail.com

I don't mind if students/teachers do a selected printout of these questions and answers.


You are given four pairs of haloalkane isomers, answer the questions with as much reasoning as possible.

Q1 Name A to H with IUPAC names and give their classification as primary (prim), secondary (sec) or tertiary (tert).

ANSWERS

A 1-bromopentane (prim),  B 2-fluoropentane (sec),  C 3-iodopentane (sec)

D 1-chloro-2-methylbutane (prim),  E 1-fluoro-3-methylbutane (prim),  F 2-iodo-2-methylbutane (tert)

G 2-bromo-3-methylbutane (sec),  H 1-chloro-2,2-dimethylpropane (prim)


Q2 (a) Which will on hydrolysis aqueous sodium hydroxide, will yield a secondary alcohol?

(b) Write a skeletal formula equation for one of the hydrolysis reactions and state the name of the product and what type of mechanism pathway the reaction will take.

(c) Explain which of them is likely to react the fastest and which the slowest irrespective of the mechanistic pathway the hydrolysis takes.

(d) Which is the only one to yield a tertiary alcohol on hydrolysis

ANSWERS:

(a) B, C and G, sec haloalkane gives sec alcohol (so prim gives prim and tert gives tert)

(b) Nucleophilic substitution reactions to give:

B yields pentan-2-ol,   C yields pentan-3-ol,   G yields 3-methylbutan-2-ol

(c) C would react the fastest because the C-I bond is weaker than either the C-F or the C-Br bond, so the activation will be the lowest.

B would react the slowest because the C-F bond is stronger than the C-Br or C-I bond, so the activation will be the highest.

It is worth noting that the reactivity order does NOT fit in with trend in polarity i.e. C-F > C-Br > C-I because of the decreasing electronegativity difference.

It is the bond enthalpy trend that determines the reactivity trend C-I > C-Br > C-Cl > C-F, as the halogen atomic radius decreases, the bond length decreases and the bond enthalpy increases.

Nucleophilic substitution by water/hydroxide ion [SN1 or SN2, hydrolysis to give alcohols]


Q3 Which of the molecules will form a pair of R/S ('optical') isomers? and quote their chiral centre.

ANSWERS: B, D and G, all have C2 stereocentres i.e. in these cases, all the C2 carbon atoms have four different atoms/groups attached the same chiral carbon atom.


Q4 Which of C and F would react the fastest on refluxing with aqueous sodium hydroxide?

ANSWER: F because, for the same halogen atom, tertiary haloalkanes react faster than secondary haloalkanes (and faster than primary haloalkanes).

Nucleophilic substitution by water/hydroxide ion [SN1 or SN2, hydrolysis to give alcohols]


Q5 Which of E and H would react the fastest on refluxing with aqueous sodium hydroxide?

ANSWER: H because the C-Cl bond enthalpy is less than the C-F bond enthalpy, so the H reaction has a lower activation energy - note you are comparing two primary haloalkanes - fair test!

Nucleophilic substitution by water/hydroxide ion [SN1 or SN2, hydrolysis to give alcohols]


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