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Advanced A level physical chemistry extra exam revision notes
on:
Ionic bonding and ionic compounds
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Part 6.
Extra advanced level chemical bonding notes
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Ionic bonding and advanced electron notation
I'm not going to repeat the diagrams, there's
no point, so I'm just outlining the ionic bond formation in s, p and d terms.
Most involve the 'octet rule' to form a noble
gas electron configuration.
Examples
You need to be able to write the electron
configuration of ions in terms of s, p and d orbital notation.
e.g. sodium ion Na+ is 1s22s2p6
= [Ne], and the chloride ion Cl- is 1s22s2p63s23p6
= [Ar]
More on
electron configuration of ions and
oxidation states
Which elements form
ionic compounds? and how to work out and write an ionic formula?
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Pd |
metals |
Part of the modern Periodic Table
related to selected elements that form ionic compounds
Pd = period,
Gp = group |
metals =>
non–metals |
|
Gp1 |
Gp2 |
Gp3 |
Gp4 |
Gp5 |
Gp6 |
Gp7 |
Gp0 |
|
1 |
1H Note
that H does not readily fit into any group
|
2He |
|
2 |
3Li |
4Be |
atomic number
Chemical Symbol eg 4Be |
5B |
6C |
7N |
8O |
9F |
10Ne |
|
3 |
11Na |
12Mg |
13Al |
14Si |
15P |
16S |
17Cl |
18Ar |
|
4 |
19K |
20Ca |
21Sc |
22Ti |
23V |
24Cr |
25Mn |
26Fe |
27Co |
28Ni |
29Cu |
30Zn |
31Ga |
32Ge |
33As |
34Se |
35Br |
36Kr |
|
5 |
37Rb |
38Sr |
39Y |
40Zr |
41Nb |
42Mo |
43Tc |
44Ru |
45Rh |
46Pd |
47Ag |
48Cd |
49In |
50Sn |
51Sb |
52Te |
53I |
54Xe |
|
6 |
55Cs |
56Ba |
Transition Metals |
81Tl |
82Pb |
83Bi |
84Po |
85At |
86Rn |
|
Gp
1 Alkali Metals
Gp 2 Alkaline Earth Metals
Gp 7/17 Halogens
Gp 0/18 Noble Gases
Chemical bonding comments about the
selected elements highlighted in white
e.g. When the electropositive metals on the left
combine with the non–metals on the right, quite often ionic bond is
formed e.g. the formation of an ionic compound like sodium
chloride NaCl
Note:
Throughout this page to form stable ions with a noble gas
electron arrangement by electron transfer ...
(a) Group 1 metals lose their 1 outer
electron to form a singly charged positive ion: M ==> M+
+ e–
(b) Group 2 metals
lose their 2 outer electrons to form a doubly charged positive
ion: M ==> M2+ + 2e–
(c) Group 6 non–metals gain 2 electrons to
form a doubly charged negative ion: X + 2e– ==> X2–
(d) Group 7 halogen non–metals gain 1
electron to form a singly charged negative ion: X + e–
==> X–
In a correct ionic formula: total positive
ion charge = total negative ion charge
therefore we can predict the following
formula where M = a group 1/2 metal and
X = a group 6/7 non–metal:
(a) Group 1 + (c) Group 6
===> M2X or (M+)2X2–
(eg group 1 oxides or sulfides)
(a) Group 1 + (d) Group 7/17 ===>
MX or
M+X– (eg group 1 halides)
(b) Group 2 + (c) Group 6/16
===> MX or
M2+X2– (eg group 2 oxides
or sulfides)
(b) Group 2 + (d) Group 7/17
===> MX2 or
M2+(X–)2 (eg
group 2 halides)
Atoms of groups 4/14 and 5/15 may also form ions in combination
with very electropositive metals
examples – showing the formation of a
noble gas structure
Group 4/14:
carbon forms ionic carbides: C (2.4) + 4e– ==> C4–
(carbide ion, 2.8)
examples: sodium carbide Na4C,
magnesium carbide Mg2C
Group 5/15: nitrogen forms ionic
nitrides: N (2.5) + 3– ==> N3– (nitride
ion, 2.8)
Group 5/15:
phosphorus forms ionic phosphides: P (2.8.5) + 3– ==> P3–
(nitride ion, 2.8)
examples: potassium nitride K3N,
magnesium nitride Mg2N3, sodium phosphide
Na3P
formulae derived from Na+, K+,
Mg2+ (see next section on working out ionic formulae)
Note that the
3d block – transition metals
also form many simple ionic compounds with the more
electronegative non–metals e.g. Sc2O3 and
ZnO
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Examples
of how to work out an ionic formula
numerical ion charges = the valency of A and
B to deduce the
formula AxBy
i.e. the valence or ionic charge = the combining power
of the ion
'molecular' or ionic style of formula and compound name
are shown
In the electrically
balanced formula for a potentially stable compound, the total positive ionic charge must
equal the total negative ionic charge.
number of positive ion 'A' x
positive charge of ion 'A' = number of negative ion 'B' x negative charge of ion 'B' (you
ignore charge sign)
Example: A moderately
difficult example to work out!
Aluminium oxide
consists of aluminium ions Al3+ and oxide ions
O2–
number of Al3+
x charge on Al3+ = number of O2– x
charge on O2–
the
simplest whole number
ratios
are 2 of Al3+ x 3 = 3 of O2– x 2
(total 6+ balances total 6–)
so the
simplest whole
number formula for aluminium oxide is Al2O3 which
is its empirical formula
More
examples of how to work out ionic formulae
1
of K+ balances
1 of Br– because 1
x 1 = 1 x 1 gives KBr or K+Br–
potassium bromide2
of Na+ balances
1 of O2– because 2 x 1 = 1 x 2 gives Na2O or (Na+)2O2– sodium oxide
1
of Mg2+ balances
2 of Cl– because 1 x 2 = 2 x 1 gives MgCl2 or Mg2+(Cl–)2 magnesium chloride
1
of Fe3+ balances
3 of F– because 1 x 3 = 3 x 1 gives FeF3 or Fe3+(F–)3 iron(III) fluoride
1
of Ca2+ balances
2 of NO3– because 1 x 2 = 2 x 1 gives Ca(NO3)2
or Ca2+(NO3–)2 calcium
nitrate2
of Fe3+ balances
3 of SO42– because 2 x 3 = 3 x 2 gives Fe2(SO4)3 or (Fe3+)2(SO42–)3
iron(III) sulfate
LINK to
Table
of lots of common formulae of ionic compounds
(includes common oxides, hydroxides, carbonates,
hydrogencarbonates, halides, sulfates, nitrates)
At Advanced A level you would be expected to work out any
ionic formulae from given ions and you should know many of them anyway, or work
out the charge on the ion from the position of the element in the periodic table
and using the octet electron rule eg for groups 1, 2, 3/13, 4/14, 5/15, 6/16,
7/17, 0/18.
Naming ionic
inorganic compounds
When combined with
other elements in simple compounds the name of the non-metallic
element changes
slightly from ...??? to ...ide.
Sulfur forms a sulfide (ion S2-), oxygen forms an oxide (ion
O2-), fluorine forms a
fluoride (ion F-), chlorine forms a chloride
(ion Cl-), bromine a bromide (ion Br-) and
iodine an iodide (ion I-).
The other element at
the start of the compound name e.g. hydrogen or a metal like sodium, potassium,
magnesium, calcium, etc. remains unchanged because there is only one
oxidation state.
So typical
compound names are, sodium sulfide, hydrogen sulfide,
magnesium oxide, potassium fluoride, hydrogen
chloride, sodium chloride, calcium bromide, magnesium iodide etc.
However, with different oxidation
states the complications will arise e.g.
(i) Where an element
can form two different compounds with different formulae with the same
element there needs to be a way of expressing it in the name as well as
in the formula e.g.
iron(II)
chloride, FeCl2 and iron(III) chloride, FeCl3
copper(I) oxide,
Cu2O and copper(II) oxide, CuO
Hear chlorine has a
combining power of 1 (valence 1) and oxygen 2 in both compounds.
However, iron can
have a valence of 2 or 3 and copper 1 or 2 and these also correspond
numerically to the charge on the metal ions in such compounds e.g. Fe2+
and Fe3+, Cu+ and Cu2+.
Therefore the 'Roman
numerals' number in (brackets) gives the valence of the element in that
particular compound. At a higher academic level this is known as the
oxidation state.
(ii) When the
non-metal is combined with oxygen to form a negative ion (anion) ion
which combines with a positive ion (cation) from hydrogen or a metal, then
the
end of the 2nd part of the name ends in ...ate or ...ite e.g.
NO3 in a
compound formula is nitrate e.g. KNO3, potassium nitrate.
SO3 in a
formula is sulphite, e.g. Na2SO3, sodium sulphite,
SO4 is
sulfate, e.g. MgSO4, magnesium sulfate,
PO4 is
phosphate, e.g. Na2HPO4, disodium hydrogen
phosphate
For elements (metal or non–metal) combined with oxygen or other
more electronegative element, giving an anion, the ion name
ends in ...ate with the prefix derived from the elements
name.
In such cases the oxygen carries the negative oxidation state of
(–2) or chlorine (–1) e.g.
-
vanadate(V)
ion, VO43–,
-
manganate(VI)
ion,
MnO42–, manganate(VII) ion,
MnO4–, (was called the permanganate
ion)
-
sulfate(IV)
ion, SO32–
(sulphite) and sulfate(VI)
ion,SO42–
(sulfate)
-
nitrate(III),
NO2– (nitrite) and nitrate(V), NO3– (nitrate)
-
chlorate(I),
ClO–, chlorate(VII), ClO4–
etc. oxygen is more electronegative than chlorine.
transition
metal complex anions e.g.
tetrachlorocuprate(II) ion, [CuCl4]2–
(oxidation states Cu +2, Cl –1)
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