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School-college Physics Notes: SOUND 7. ULTRASOUND and uses

SOUND  7. ULTRASOUND - very high frequency sound waves, definition, examples described, uses, speed and sound wave calculations, echo sounding (echo-location), bats, medical uses e.g. scanning

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7. ULTRASOUND - definition, examples described, uses and calculations

As already mentioned, you can use a signal generators to produce electrical oscillations of any frequency.

The electrical oscillations are converted to mechanical vibrations producing sound waves.

The sound waves can be produced to well beyond the range of human hearing.

The high frequencies are above 20 kHz (20000 Hz) and are known as ultrasound.

Ultrasound waves behave like any other waves, they can be absorbed, reflected or refracted.

The reflection and refraction effects can be used to measure distances and 3D scanning with sonar searching and medical imaging applications.

In physics the term “ultrasound” applies to all acoustic energy sound waves with a frequency above typical human hearing (20,000 hertz or 20 kilohertz). Typical diagnostic sonographic scanners used in various applications operate in the frequency range of 2 to 18 megahertz (2-18 x 106 Hz), which is hundreds of times greater than the limit of human hearing.

 

Medical uses of ultrasound

Ultrasound of very high frequency sound waves are used in scanning pregnant women to monitor the progress of unborn baby.

The ultrasound waves enter the woman's body and the echoes-reflections are picked up by a microphone and converted into electronic signals from a which an internal picture of the womb can be constructed.

Ultrasound is considered a safe technique for pre-natal scanning of a foetus, various soft-tissue organs and is much safer than using dangerous X-rays.

Tissues e.g. muscle, stomach, womb or fluids of different density give different intensities of reflection and so differentiation of the structure of the womb, foetus or baby can be seen - modern ultrasound scanners can produce quite high resolution images.

The speed of ultrasound is different in different tissues and the ultrasound scanner is able to work out the distance between different boundaries and construct a '3D' image of the developing foetus in the womb.

Ultrasound can also be used in the 'medical imaging' of soft tissue organs like the bladder, kidneys and liver.

The scans can detect changes in the structure of these organs and help diagnose medical conditions associated with them.

Although medical imaging using ultrasound is quite safe, the images are not sharp enough to replace the use of X-rays for investigating bone structure.

Note that a gel is placed on the patient's body between the ultrasound probe and their skin.

The gel ensures that most of the ultrasound would be refracted at the skin and a good image of the internal structure of the body could not be obtained.

 

More on how does ultrasound scanning works

When sound waves (in this case ultrasound) are passing from one medium to another (solid or liquid - body fluid, tissue, bone, organs etc.) some are partially reflected, and some are transmitted and refracted at the boundary interface (see the diagram on the right of wavefronts meeting a boundary between two media).

In foetal scanning, the two media would be the fluid in the woman's womb and the skin and tissue of the growing foetus.

The time for reflections to take place at a particular angle is measured i.e. the time it takes for the sound impulses to be emitted from the transmitter and reflected back off a boundary and the return signals picked up by the detector.

From the reflections, it is the echo time intervals that allows a distance to be calculated by the computer and their distribution allows a 3D image to be built up.

The recorded data is processed by a computer to build up a 3D video on the screen from which individual images can be viewed and even printed out (for medical checks-investigation and hopefully for the delight of expectant parents).

This form of medical imaging works because ultrasound waves can pass through the body but if they meet a boundary e.g. between fluid and tissue some of the waves are reflected.

It is the distribution of these echo signals that enables the computer to build up the image.

 

Treatment of kidney stones

The patient lies on a water-filled cushion, and the surgeon uses X-rays or ultrasound tests to precisely locate the kidney stone.

Ultrasound shock waves are then sent to the stone from a machine to break it into smaller pieces that can be carried in your urine and pass through the urinary tract and out of your body - job done!

 

Industrial uses of ultrasound

Ultrasound is used to detect flaws in manufactured products such metal castings or pipes.

Ultrasound waves, after entering a material are usually reflected back by the far side of a object.

If there is a flaw in the casting or the welding of an object, when scanned with ultrasound the flaws show up as some of the waves are reflected-deflected back where you might expect them to go right through the object to the other side.

In other words if there is an internal flaw in the object e.g. a weld joint, the ultrasound is reflected back sooner than expected.

The same technique is used on test trains to check for flaws in railway tracks e.g. cracks in train rails.

An ultrasound beam can be used to measure the thickness of a material by detecting the reflection from both surfaces.

 

Use of ultrasound for sonar - echo sounding

Ultrasound systems are used by small boats, ships and submarines for echo sounding.

You need a transmitter and receiver and from the echo signals you can get the distance to the seabed.

With more sophisticated systems you can get an 'underwater picture' of what's there e.g. shoal of fish, sunken wreck, dangerous underwater rocks.

The signal time of the echo can be used to measure the depth of water beneath a boat.

If d = depth of water (m), if t = time of echo signal 'there and back' (s), v = speed of sound wave (m/s)

v = d / t, therefore depth d = v x (t / 2) (m/s)

BUT, note that the time is halved because the sound is 'going there and back' in the time interval t.

 

Bats and ultrasound!

Bats are amongst other animals, such as cats and dogs,  that can hear high frequency sounds.

Bats emit pulses of sound of 20 000 Hz to 100 00 Hz to find their way around using echo location.

Their large ears pick up reflected sounds and their brain builds up a 'picture' of the 3D world in front of them.

 

study the mole examples carefully A tale of the mole!  (but NOT the chemical quantity the 'mole')

mole hill on a lawn ultrasound mole repellant buried in a lawn

In September 2023 a European mole (Talpa europaea) decided to take up residence in our garden and has had a great time excavating the lawn and producing some very neat mole hills of excellent quality soil.

Internet research revealed that a humane method of inhibiting their presence was to buy an ultrasound emitter and bury it into the ground where mole activity was present and to be discouraged. They don't like higher pitched sounds  or loud sounds.

Theoretically ultrasonic mole repellers are supposed to emit ultrasound waves that are inaudible to humans but extremely irritating to moles. Moles can detect infrasound, that is sound waves of less than 20 Hz.

I purchased a pair of these mole repellent ultrasound emitters, fitted the batteries in and buried them at either end of the lawn. These typically operate with frequencies of 400 to 1000 Hz and these frequencies moles find irritating (technically this is not ultrasound and better described as a sonic pulse).

However other ultrasonic pest repellers produce sound at frequencies that are intolerable to pests like moles but inaudible to humans. Electronic pest repellers' frequencies typically fall between 20 kHz and 100 kHz, that is frequencies well normal human hearing.

The sonic devices I purchased did seem to work at first, but the mole just moved to other areas in the garden, some I'm not really sure it was worth the financial and physical effort involved in my sonic garden mole repeller project. The general consensus is that they are not that effective.

However, it is another description of the use of sound and might come in handy in a more open-ended exam question on the applications of sound technology.

So, rather than resort to nasty chemicals I've decide to pay homage to the evolutionary traits developed by the mole - however annoying they are!

In evolutionary terms, the mole is an inspiring 'integrated science' subject and well adapted for life underground. It lives off worms, grubs and insects, but the problem is where they forage for food, but some of the advantages evolutionary traits are:

(a) Greatly enlarged front feet that are strong and good for digging and soil removal.

(b) Mole fur is short and smooth, almost like velvet and this minimises friction when moving through narrow soil tunnels (physics).

(c) Moles have a thin layer of skin over their eyes to protect them from soil falling on them, the eyes are only 1 mm in diameter.

(d) Moles do not have prominent ears, they have small holes in the skull covered with a thin layer of skin to keep the soil out. They can detect relative low frequencies of sound and do not like higher frequency sounds (physics).

(e) Moles are tolerant to high concentrations of carbon dioxide in the air, as carbon dioxide levels will build up at times in the confined spaces of their tunnel network (biochemistry).

(f) They can re-breath in expelled air to extract more oxygen - this links in with (e).

(f) The haemoglobin (hemoglobin) molecules in their blood are more efficient in carrying oxygen than many other mammals including us and this enables them to tolerate lower levels of oxygen in the underground air (which of course will be coincident with higher levels of carbon dioxide, biochemistry).

 

Calculations involving ultrasound waves and echo sounding

Be able to use both the equations below, which apply to sound waves (and their rearrangements):

appropriate units used in ()

a) sound wave speed (metre/second, m/s) = frequency (hertz, Hz) x wavelength (metre, m)

in 'shorthand'    v = f x λ

rearrangements:  f = v ÷ λ   and   λ = v ÷ f

b) sound wave speed (metre/second, m/s) = distance (metre, m) / time (second, s)

in 'shorthand'    v = d ÷ t

rearrangements:  d = v x t   and   t = d ÷ v

This is the general formula for the speed or velocity of anything moving.

Equation (a) equation (b)

 

Q1 A pulse of ultrasound from a fishing boat takes 1.40 seconds to travel from the boat down to the seabed and back to the 'microphone' detector.

If the speed of sound in seawater is 1530 m/s calculate the depth of the water at that point.

Worked out ANSWERS to the 'echo' calculation questions

 

Q2 The speed of sound in seawater is 1530 m/s.

How long will it take an ultrasound signal to be transmitted and received after reflecting back from a shoal of fish swimming at a depth of 200 m? (give your answer to two significant figures)

Worked out ANSWERS to the 'echo' calculation questions

 

Q3 In misty weather, a ship sounds a foghorn warning when near a coastline of cliffs.

If the echo is heard 5.0 seconds later, how far away are the reflecting cliffs if the seed of sound is 340 m/s?

Worked out ANSWERS to the 'echo' calculation questions

 

Q4 Suppose the time difference is 150 µs between two pulses from either side of the head of a fetus in a woman's womb.

If the speed of ultrasound is 1540 m/s, calculate the size of the baby's head in cm.

Worked out ANSWERS to the 'echo' calculation questions

 

INDEX of physics notes on SOUND


Keywords, phrases and learning objectives for ultrasound waves

Know that ultrasound is very high frequency sound waves that humans cannot hear but bats can, which they use for 'echo location'.

Be able to describe examples of the uses of ultrasound e.g. foetal scanning and depth sounding and scanning using emitted ultrasound from a boat.

Be able to speed and echo sound wave calculations


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INDEX of physics notes on SOUND

Worked out ANSWERS to the 'echo' calculation questions.

Q1 A pulse of ultrasound from a fishing boat takes 1.40 seconds to travel from the boat down to the seabed and back to the 'microphone' detector.

If the speed of sound in seawater is 1530 m/s calculate the depth of the water at that point.

speed = distance / time, rearranging gives d = s x t,

but you halve the time t to 0.70 seconds because of the double journey (there and back) of the wave.

Therefore depth = 1530 x 0.70 = 1070 m (3 s.f.)

 

Q2 The speed of sound in seawater is 1530 m/s.

How long will it take an ultrasound signal to be transmitted and received after reflecting back from a shoal of fish swimming at a depth of 200 m? (give your answer to two significant figures)

speed = distance /time, time = distance / speed

time = (200 x 2) / 1530 = 0.26 s (2 sf)

 

Q3 In misty weather, a ship sounds a foghorn warning when near a coastline of cliffs.

If the echo is heard 5.0 seconds later, how far away are the reflecting cliffs if the seed of sound is 340 m/s?

v = d / t, so d = v x t, d = distance to cliffs, v = 340 m/s, t = 5.0 / 2 = 2.5 s,

distance = 340 x 2.5 = 850 m

 

Q4 Suppose the time difference is 150 µs between two pulses from either side of the head of a fetus in a woman's womb.

If the speed of ultrasound is 1540 m/s, calculate the size of the baby's head in cm.

s = d / t, rearranging gives d = s x t, but d = twice the width of the head ('there and reflection back'),

size of baby's head = (1540 x 150 x 10-6 ) ÷ 2 =  0.1155 m = 11.6 cm (3 sf)

(note that µs = microseconds, 10-6 factor)

 

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