12. GCSE level
chemical calculations for volumetric titration calculations - acid-alkali
titrations (M = mol/dm3)
Given the neutralisation equation: NaOH(aq) + HCl(aq) ==> NaCl(aq) + H2O(l) 25 cm3 of hydrochloric acid are neutralised by 20 cm3 of 0.05M sodium hydroxide. What is the molarity of the acid? [vct-1]
0.04
0.02
1.25
0.80
Given the neutralisation equation: NaOH(aq) + HCl(aq) ==> NaCl(aq) + H2O(l) 15 cm3 of hydrochloric acid are neutralised by 25 cm3 of 0.06M sodium hydroxide. What is the molarity of the acid? [vct-2]
0.40
0.10
0.04
0.01
Given the neutralisation equation: NaOH(aq) + HCl(aq) ==> NaCl(aq) + H2O(l) 40 cm3 of 0.05M hydrochloric acid are neutralised by 20 cm3 of a sodium hydroxide solution. What is the molarity of the alkali? [vct-3]
0.20
0.05
0.10
0.50
Given the neutralisation equation: NaOH(aq) + HCl(aq) ==> NaCl(aq) + H2O(l) 25 cm3 of 0.16M hydrochloric acid are neutralised by 10 cm3 of a sodium hydroxide solution. What is the molarity of the alkali? [vct-4]
0.2
0.1
0.8
0.4
Given the neutralisation equation: 2KOH(aq) + H2SO4(aq) ==> K2SO4(aq) + 2H2O(l) What is the molarity of a sulfuric acid solution, if 15 cm3 of it are neutralised by 20 cm3 of a 0.3 M potassium hydroxide solution? [vct-5]
0.20
0.15
0.40
0.75
Given the neutralisation equation: 2KOH(aq) + H2SO4(aq) ==> K2SO4(aq) + 2H2O(l) What is the molarity of a sulfuric acid solution, if 30 cm3 of it are neutralised by 10 cm3 of a 0.6 M potassium hydroxide solution? [vct-6]
0.20
0.10
0.05
0.25
Given the neutralisation equation: 2KOH(aq) + H2SO4(aq) ==> K2SO4(aq) +2H2O(l) What is the molarity of a potassium hydroxide solution, if 10 cm3 of it are neutralised by 12 cm3 of a 0.5 M sulfuric acid solution? [vct-7]
2.4
0.6
1.2
0.6
Given the neutralisation equation: 2KOH(aq) + H2SO4(aq) ==> K2SO4(aq) + 2H2O(l) What is the molarity of a potassium hydroxide solution, if 5 cm3 of it are neutralised by 20 cm3 of a 1 M sulfuric acid solution? [vct-8]
16
4
5
8
Given the neutralisation equation: 3NaOH(aq) + H3PO4(aq) ==> Na3PO4(aq) + 3H2O(l) What is the molarity of a phosphoric acid solution, if 15 cm3 of it are neutralised by 22.5 cm3 of a 0.2 M sodium hydroxide solution? [vct-9]
0.10
0.30
0.03
0.01
Given the neutralisation equation: 3NaOH(aq) + H3PO4(aq) ==> Na3PO4(aq) + 3H2O(l) What is the molarity of a phosphoric acid solution, if 40 cm3 of it are neutralised by 15 cm3 of a 0.4 M sodium hydroxide solution? [vct-10]
0.150
0.050
0.017
0.115
Given the neutralisation equation: 3NaOH(aq) + H3PO4(aq) ==> Na3PO4(aq) + 3H2O(l) What is the molarity of a sodium hydroxide solution, if 21.6 cm3 of it are neutralised by 18 cm3 of a 0.2 M phosphoric acid solution? [vct-11]
1.50
1.15
0.50
0.17
Given the neutralisation equation: 3NaOH(aq) + H3PO4(aq) ==> Na3PO4(aq) + 3H2O(l) What is the molarity of a sodium hydroxide solution, if 15 cm3 of it are neutralised by 20 cm3 of a 0.6 M phosphoric acid solution? [vct-12]
1.2
7.2
0.8
2.4
Given the neutralisation equation: NaOH(aq) + HCl(aq) ==> NaCl(aq) + H2O(l) 25 cm3 of hydrochloric acid are neutralised by 20 cm3 of 0.05M sodium hydroxide. What is the molarity of the acid? [vct-1]
Given the neutralisation equation: NaOH(aq) + HCl(aq) ==> NaCl(aq) + H2O(l) 15 cm3 of hydrochloric acid are neutralised by 25 cm3 of 0.06M sodium hydroxide. What is the molarity of the acid? [vct-2]
Given the neutralisation equation: NaOH(aq) + HCl(aq) ==> NaCl(aq) + H2O(l) 40 cm3 of 0.05M hydrochloric acid are neutralised by 20 cm3 of a sodium hydroxide solution. What is the molarity of the alkali? [vct-3]
Given the neutralisation equation: NaOH(aq) + HCl(aq) ==> NaCl(aq) + H2O(l) 25 cm3 of 0.16M hydrochloric acid are neutralised by 10 cm3 of a sodium hydroxide solution. What is the molarity of the alkali? [vct-4]
Given the neutralisation equation: 2KOH(aq) + H2SO4(aq) ==> K2SO4(aq) + 2H2O(l) What is the molarity of a sulfuric acid solution, if 15 cm3 of it are neutralised by 20 cm3 of a 0.3 M potassium hydroxide solution? [vct-5]
Given the neutralisation equation: 2KOH(aq) + H2SO4(aq) ==> K2SO4(aq) + 2H2O(l) What is the molarity of a sulfuric acid solution, if 30 cm3 of it are neutralised by 10 cm3 of a 0.6 M potassium hydroxide solution? [vct-6]
Given the neutralisation equation: 2KOH(aq) + H2SO4(aq) ==> K2SO4(aq) +2H2O(l) What is the molarity of a potassium hydroxide solution, if 10 cm3 of it are neutralised by 12 cm3 of a 0.5 M sulfuric acid solution? [vct-7]
Given the neutralisation equation: 2KOH(aq) + H2SO4(aq) ==> K2SO4(aq) + 2H2O(l) What is the molarity of a potassium hydroxide solution, if 5 cm3 of it are neutralised by 20 cm3 of a 1 M sulfuric acid solution? [vct-8]
Given the neutralisation equation: 3NaOH(aq) + H3PO4(aq) ==> Na3PO4(aq) + 3H2O(l) What is the molarity of a phosphoric acid solution, if 15 cm3 of it are neutralised by 22.5 cm3 of a 0.2 M sodium hydroxide solution? [vct-9]
Given the neutralisation equation: 3NaOH(aq) + H3PO4(aq) ==> Na3PO4(aq) + 3H2O(l) What is the molarity of a phosphoric acid solution, if 40 cm3 of it are neutralised by 15 cm3 of a 0.4 M sodium hydroxide solution? [vct-10]
Given the neutralisation equation: 3NaOH(aq) + H3PO4(aq) ==> Na3PO4(aq) + 3H2O(l) What is the molarity of a sodium hydroxide solution, if 21.6 cm3 of it are neutralised by 18 cm3 of a 0.2 M phosphoric acid solution? [vct-11]
Given the neutralisation equation: 3NaOH(aq) + H3PO4(aq) ==> Na3PO4(aq) + 3H2O(l) What is the molarity of a sodium hydroxide solution, if 15 cm3 of it are neutralised by 20 cm3 of a 0.6 M phosphoric acid solution? [vct-12]
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Given the neutralisation equation: