Quiz 3 "The Law of Conservation of Mass - simple reacting mass calculations" @ doc Brown's chemistry
Given the following symbol equation: 2Mg + O2 ==> 2MgO Calculate how many g of magnesium oxide is formed by burning 24g of magnesium in air. (Relative atomic masses, Ar: Mg = 24 and O = 16) [com-1]
40
16
20
80
Given the following symbol equation: 2Mg + O2 ==> 2MgO Calculate how many tonne of magnesium is needed to make 80 tonne of magnesium oxide. (Relative atomic masses, Ar: Mg = 24 and O = 16) [com-2]
96
48
24
16
Given the following symbol equation: CaCO3(s) ==> CaO(s) + CO2(g) Calculate how many kg of calcium carbonate is needed to make 56 kg of calcium oxide. (Relative atomic masses, Ar: Ca = 40, C = 12 and O = 16) [com-3]
50
44
100
40
Given the following symbol equation: CaCO3(s) ==> CaO(s) + CO2(g) Calculate how many g of carbon dioxide is formed if 25g of calcium carbonate is decomposed on heating to form 14g of calcium oxide. (Relative atomic masses, Ar: Ca = 40, C = 12 and O = 16) [com-4]
22
44
10
11
Given the symbol equation to show the formation of iron sulphide: Fe + S ==> FeS Calculate the mass in g of iron sulphide formed when 5.6g of iron combines with 3.2g of sulphur. (Relative atomic masses, Ar: Fe = 56 and S = 32) [com-5]
8.8
2.4
5.6
3.2
Given the symbol equation to show the formation of iron sulphide: Fe + S ==> FeS Calculate the mass in g of iron sulphide formed when 28g of iron combines with 16g of sulphur. (Relative atomic masses, Ar: Fe = 56 and S = 32) [com-6]
12
44
28
16
Given the symbol equation to show the formation of calcium chloride by burning calcium in chlorine: Ca(s) + Cl2(g) ==> CaCl2(s) Calculate the mass in g of calcium chloride formed when 20g of calcium combines with 35.5g of chlorine. (Relative atomic masses, Ar: Ca = 40 and Cl = 35.5) [com-7]
15.5
70.0
55.5
17.5
Given the symbol equation to show the formation of calcium chloride by burning calcium in chlorine: Ca(s) + Cl2(g) ==> CaCl2(s) Calculate the mass in g of chlorine needed when 40g of calcium forms 111g of calcium chloride. (Relative atomic masses, Ar: Ca = 40 and Cl = 35.5) [com-8]
80
100
151
71
Given the symbol equation to show the formation of aluminium sulphide by heating a mixture of aluminium and sulphur: 2Al + 3S ==> Al2S3 How many g of sulphur is needed if 54g of aluminium is reacted to form 150g of aluminium sulphide? (Relative atomic masses, Ar: Al = 27 and S = 32) [com-9]
96
204
64
27
Given the symbol equation to show the formation of aluminium sulphide by heating a mixture of aluminium and sulphur: 2Al + 3S ==> Al2S3 How many kg of sulphur is needed if 108kg of aluminium is reacted to form 300kg of aluminium sulphide? (Relative atomic masses, Ar: Al = 27 and S = 32) [com-10]
408
192
96
32
Given the symbol equation to show the formation of iron sulphide by heating a mixture of iron and sulphur: Fe + S ==> FeS Calculate the mass in g of iron unreacted when 60g of iron reacts with 32g of sulphur to form 88g of iron sulphide. (Relative atomic masses, Ar: Fe = 56 and S = 32) [com-11]
8
32
4
56
Given the symbol equation to show the formation of iron sulphide by heating a mixture of iron and sulphur: Fe + S ==> FeS Calculate the mass in g of sulphur unreacted when 28g of iron reacts with 22g of sulphur to form 44g of iron sulphide. (Relative atomic masses, Ar: Fe = 56 and S = 32) [com-12]
22
16
12
6
Given the symbol equation to show the formation of calcium chloride by burning calcium in chlorine: Ca(s) + Cl2(g) ==> CaCl2(s) Calculate the mass in g of calcium left unreacted when 25g of calcium reacts with 35.5g of chlorine. (Relative atomic masses, Ar: Ca = 40 and Cl = 35.5) [com-13]
10.5
5.0
7.1
12.5
Given the symbol equation to show the formation of calcium chloride by burning calcium in chlorine: Ca(s) + Cl2(g) ==> CaCl2(s) Calculate the mass in g of chlorine left unreacted when 80g of calcium reacts with 150g of chlorine to form 222g of calcium chloride. (Relative atomic masses, Ar: Ca = 40 and Cl = 35.5) [com-14]
70
8
16
72
Given the equation: Mg(OH)2 + 2HNO3 ====> Mg(NO3)2 + 2H2O How many oxygen atoms are involved in the reaction equation? [com-15]
8
16
4
6
Given the equation: Mg(OH)2 + 2HNO3 ====> Mg(NO3)2 + 2H2O How many hydrogen atoms are involved in the reaction equation? [com-16]
8
4
2
6
Given the equation: Al2O3 + 3H2SO4 ====> Al2(SO4)3 + 3H2O How many oxygen atoms are involved in the reaction equation? [com-17]
3
12
15
30
Given the equation: Al2O3 + 3H2SO4 ====> Al2(SO4)3 + 3H2O How many hydrogen atoms are involved in the reaction equation? [com-18]
2
3
12
6
When magnesium carbonate is heated strongly in a crucible, it loses a significant amount of weight. Which of the following statements is NOT TRUE? [com-19]
The apparent loss in weight is most likely due to an error in weighings.
The apparent loss in weight is due to a chemical change.
the mass of products always equals the mass of reactants.
the atoms have rearranged themselves.
When magnesium carbonate is heated strongly in a crucible, it loses a significant amount of weight. Which of the following statements is NOT TRUE? [com-20]
The apparent loss in weight is due to the formation of a gas.
The apparent loss in weight is due to a physical change of state.
the mass of products always equals the mass of reactants.
the atoms have rearranged themselves.
When magnesium carbonate is heated strongly in a crucible, it loses a significant amount of weight. Which of the following statements is NOT TRUE? [com-21]
The apparent loss in weight is due to the formation of a gas.
The apparent loss in weight is only due to a chemical change.
the mass of products is less than the mass of reactants.
the atoms have rearranged themselves.
When magnesium carbonate is heated strongly in a crucible, it loses a significant amount of weight. Which of the following statements is NOT TRUE? [com-22]
The apparent loss in weight is due to the formation of a gas.
The apparent loss in weight is only due to a chemical change.
the mass of products always equals the mass of reactants.
the atoms have become lighter on heating.
Given the following symbol equation: 2Mg + O2 ==> 2MgO Calculate how many g of magnesium oxide is formed by burning 24g of magnesium in air (2sf). (Relative atomic masses, Ar: Mg = 24 and O = 16) [com-1]
Given the following symbol equation: 2Mg + O2 ==> 2MgO Calculate how many tonne of magnesium is needed to make 80 tonne of magnesium oxide (2sf). (Relative atomic masses, Ar: Mg = 24 and O = 16) [com-2]
Given the following symbol equation: CaCO3(s) ==> CaO(s) + CO2(g) Calculate how many kg of calcium carbonate is needed to make 56 kg of calcium oxide (3sf). (Relative atomic masses, Ar: Ca = 40, C = 12 and O = 16) [com-3]
Given the following symbol equation: CaCO3(s) ==> CaO(s) + CO2(g) Calculate how many g of carbon dioxide is formed if 25g of calcium carbonate is decomposed on heating to form 14g of calcium oxide (2sf). (Relative atomic masses, Ar: Ca = 40, C = 12 and O = 16) [com-4]
Given the symbol equation to show the formation of iron sulphide: Fe + S ==> FeS Calculate the mass in g of iron sulphide formed when 5.6g of iron combines with 3.2g of sulphur (2sf). (Relative atomic masses, Ar: Fe = 56 and S = 32) [com-5]
Given the symbol equation to show the formation of iron sulphide: Fe + S ==> FeS Calculate the mass in g of iron sulphide formed when 28g of iron combines with 16g of sulphur (2sf). (Relative atomic masses, Ar: Fe = 56 and S = 32) [com-6]
Given the symbol equation to show the formation of calcium chloride by burning calcium in chlorine: Ca(s) + Cl2(g) ==> CaCl2(s) Calculate the mass in g of calcium chloride formed when 20g of calcium combines with 35.5g of chlorine (3sf). (Relative atomic masses, Ar: Ca = 40 and Cl = 35.5) [com-7]
Given the symbol equation to show the formation of calcium chloride by burning calcium in chlorine: Ca(s) + Cl2(g) ==> CaCl2(s) Calculate the mass in g of chlorine needed when 40g of calcium forms 111g of calcium chloride (2sf). (Relative atomic masses, Ar: Ca = 40 and Cl = 35.5) [com-8]
Given the symbol equation to show the formation of aluminium sulphide by heating a mixture of aluminium and sulphur: 2Al + 3S ==> Al2S3 How many g of sulphur is needed if 54g of aluminium is reacted to form 150g of aluminium sulphide? (2sf) (Relative atomic masses, Ar: Al = 27 and S = 32) [com-9]
Given the symbol equation to show the formation of aluminium sulphide by heating a mixture of aluminium and sulphur: 2Al + 3S ==> Al2S3 How many kg of sulphur is needed if 108kg of aluminium is reacted to form 300kg of aluminium sulphide? (3sf) (Relative atomic masses, Ar: Al = 27 and S = 32) [com-10]
Given the symbol equation to show the formation of iron sulphide by heating a mixture of iron and sulphur: Fe + S ==> FeS Calculate the mass in g of iron unreacted when 60.0g of iron reacts with 32.0g of sulphur to form 88g of iron sulphide. (2sf) (Relative atomic masses, Ar: Fe = 56 and S = 32) [com-11]
Given the symbol equation to show the formation of iron sulphide by heating a mixture of iron and sulphur: Fe + S ==> FeS Calculate the mass in g of sulphur unreacted when 28.0 g of iron reacts with 22.0 g of sulphur to form 44g of iron sulphide. (2sf) (Relative atomic masses, Ar: Fe = 56 and S = 32) [com-12]
Given the symbol equation to show the formation of calcium chloride by burning calcium in chlorine: Ca(s) + Cl2(g) ==> CaCl2(s) Calculate the mass in g of calcium left unreacted when 25.0 g of calcium reacts with 35.5 g of chlorine. (2sf) (Relative atomic masses, Ar: Ca = 40 and Cl = 35.5) [com-13]
Given the symbol equation to show the formation of calcium chloride by burning calcium in chlorine: Ca(s) + Cl2(g) ==> CaCl2(s) Calculate the mass in g of chlorine left unreacted when 80 g of calcium reacts with 150 g of chlorine to form 222g of calcium chloride. (2sf) (Relative atomic masses, Ar: Ca = 40 and Cl = 35.5) [com-14]
Sodium hydroxide is neutralised by hydrochloric acid to give the salt sodium chloride and water. NaOH + HCl ===> NaCl + H2O Given the relative atomic masses: Na = 23, O = 16, H = 1 and Cl = 35.5 Calculate the mass of sodium chloride produced from 40 g of sodium hydroxide? (3sf) [com-15]
Sodium hydroxide is neutralised by hydrochloric acid to give the salt sodium chloride and water. NaOH + HCl ===> NaCl + H2O Given the relative atomic masses: Na = 23, O = 16, H = 1 and Cl = 35.5 Calculate the mass of sodium chloride produced from 80 g of sodium hydroxide? (3sf) [com-16]
Sodium hydroxide is neutralised by hydrochloric acid to give the salt sodium chloride and water. NaOH + HCl ===> NaCl + H2O Given the relative atomic masses: Na = 23, O = 16, H = 1 and Cl = 35.5 Calculate the mass of sodium hydroxide is needed to make 234 g of sodium chloride? (3sf) [com-17]
Sodium hydroxide is neutralised by hydrochloric acid to give the salt sodium chloride and water. NaOH + HCl ===> NaCl + H2O Given the relative atomic masses: Na = 23, O = 16, H = 1 and Cl = 35.5 Calculate the mass of sodium hydroxide is needed to make 117 tonnes of sodium chloride? (2sf) [com-18]
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Given the following symbol equation:
Given the equation: Mg(OH)2 + 2HNO3 ====> Mg(NO3)2 + 2H2O
When magnesium carbonate is heated strongly in a crucible, it loses a significant amount of weight.
Sodium hydroxide is neutralised by hydrochloric acid to give the salt sodium chloride and water.