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Doc
Brown's Chemistry Clinic
My unofficial
support for Salters
AS
Advanced Chemistry
Salters A2 Chemistry - 'exam
bashing' thoughts for
Unit WM "What's in a
Medicine?" - part of module 2849 * My revision index
* WM
Unit map
& Learning Objectives * other
WM backup
material *
My Salters A2 page *
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At the moment the A2 links
are for the old syllabus *
My NEW Salters
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PLEASE REMEMBER, THESE ARE NOT 'STAND ALONE' NOTES, and were designed for my
classes for use alongside the Salters resources - Chemical Ideas, Chemical
Storylines, Practical Activities-Investigations and the AS-A2 Revision guides
all published by Heinemann Secondary Series, to reduce the reading workload and
offer a study strategy. From your
teacher (not me!), its handy to have the answers to the Chemical Ideas,
Storylines Assignments and Activities Questions side by side with the texts and
these strategy pages. You haven't time to redo the Q's but a quick read of the
Q's and connecting with the official answers is valuable revision - there is too
much hit and miss revision from doing past papers in my opinion.
CS
WM1 "THE DEVELOPMENT OF MODERN IDEAS ABOUT MEDICINE"
-
Main ingredients of medicines
are drugs - which are substances which alter the way your body
functions in a major/minor way - the idea being to improve bodily functions.
in a beneficial way.
-
Anything that causes some kind
of malfunction in the body is called a poison.
-
Not all drugs are medicines eg
alcohol, nicotine.
-
The study of drugs and their
action is called pharmacology and the 'art' and science of making and
dispensing medicines is called pharmacy.
-
Today's medicine molecules are
increasingly designed (sometimes on a computer!) to have specific and
maximised effects - molecular pharmacology.
Act
WM1 "The origins and development of the modern pharmaceutical industry"
-
Be able to argue a few points
for/against traditional medicine eg some traditional remedies seem to work
but not always 'explainable'
-
Sometimes the 'molecules' from
traditional plant/herbal medicines become lead (starter) molecules in drug research.
-
Deaths from disease have been
considerably reduced by pharmaceutical products (see Fig. 1).
-
But improved sanitary
conditions, purer safer water supplies as well as immunisation have also
played their part.
-
AND big killers like cancer and
heart disease are to some extent (bar DNA 'expression') in our own hands via
our life style.
-
Pharmaceutical industry a major
growth industry and a big UK money earner!
Chemical
Storylines
WM2 "MEDICINES IN NATURE"
-
Modern pharmacy has its
origins in traditional herbal medicine sometimes the 'molecules' from
traditional plant/herbal medicines become lead molecules in drug research,
ie researched, modified forms synthesised and tested.
-
Traditional
'potions' derived from willow leaves and bark were
recommended for the alleviation of pain.
-
The
active ingredient turns out to be related (in fact the precursor) of the
aspirin molecule.
Activity
WM2 "Extraction of salicylic acid"
-
The
preparative techniques of 'heating under reflux' should be known eg
brief description and diagram, it allows the reaction temperature to be
raised without losing volatile solvents, reactants or products.
-
Notes (i) that
anti-bumping granules give a smoother boiling action and
-
(ii) the cold water
enters at the base of the vertical condenser and exits at the top - allows a
safety 'cool time' if there is a water supply problem
-
and (iii) adding a strong
acid, HCl(aq), precipitates or 'frees' the weak less soluble
organic acid.
-
The
analytical technique of 'thin-layer chromatography' is
important to know, briefly how it is done and what sort of information can
be deduced.
-
The
end questions a-e are also important.
Storylines
WM3
"IDENTIFYING THE ACTIVE CHEMICAL IN WILLOW BARK"
Chemical
Ideas 13.2 "Alcohols and ethers" (revision)
CI p304-306, Q1-4 p308
-
Revise
the structure, classification (prim/sec/tert) and naming of alcohols.
-
Revise
how to draw the structures of alcohols: (i) full structural, (ii)
abbreviated structural formulae, (iii) skeletal (see p 305 above table 4).
Chemical
Ideas 13.3 "Carboxylic acids and their derivatives"
-
Its
a short section to study and from table 6 p308-309 the acid, ester, and acid
anhydride structure are the most important for unit PR.
-
For
naming aliphatic carboxylic acids, from alkane name remove the end e
and replace with ....oic acid
-
For
naming aromatics acids, most you will encounter will be based on
benzoic acid. The -COOH acts as carbon atom 1 (no need to say 1 in name),
so substituent groups are given the smallest possible numbers eg
2-hydroxybenzoic acid (from which Aspirin is made). Lots of examples on the carboxylic
acid web page.
-
Make
sure you can name, draw (structural or skeletal) or recognise carboxylic
acids and their derivatives eg CI Q's 1-5.
Chemical
Ideas new 13.4 part b "The -OH group in alcohols, phenols and carboxylic acids"
for
new CI 13.4 part a see exam bashing notes for PR
-
From CI 13.3, 13.4 and 13.5 make sure you can recognise members of the following homologous series:
-
Be able to describe and explain
the characteristic
chemical properties of alcohols, phenols
and carboxylic acids,
writing/interpreting equations, reagents
used, observations etc. including:
The focus is to study them in the context of the OH
hydroxyl group in three different 'molecular' environments.
-
acidic nature -
theory explaining relativity order of acidity, relative extent of
ionisation an anion stability
-
test with iron(III) chloride
solution, only phenols give purple colour
-
ester formation from
carboxylic acids (or derivative) + alcohol or phenol
-
AND
WATCH OUT FOR multi-functional group molecules like
2-hydroxybenzoic acid (salicylic acid)
-
-OH group gives purple
colour with iron(III) chloride
-
-OH can be esterified with
a carboxylic acid derivative like ethanoic anhydride to make an ester
(eg aspirin)
-
-COOH group can be
neutralised to form a salt with metal hydroxide or carbonate
-
-COOH group can be
esterified with an alcohol
Chemical
Ideas 13.5 Esters
-
Basic equation of
formation: R-OH + HOOC-R'
R-OOC-R' + H2O
-
or R'COOH + ROH
R'COOR + H2O
-
for the
carboxylic acid, R' = H, alkyl or aryl, and for the alcohol
R = alkyl or aryl, but for aryl not using the acid
catalyst reflux method)
-
R is alkyl for
alcohols, or aryl for phenols, R' is H, alkyl or aryl for the
carboxylic acid. Aryl means aromatic eg simplest is C6H5-
for the a benzene ring of benzoic acid.
-
Esterification
is another example of a condensation reaction. The usual catalyst
is a small amount of concentrated sulphuric acid
and the mixture heated under reflux (but
NOT for phenols, where you must use an acyl chloride or acid
anhydride).
-
Be able to
recognise the ester linkage -CO-O- as a functional
group/homologous series and to write the equation in shorthand or
full structural formula style.
-
AND recognise and
name the ester which ever way its written down!
-
Naming: The alcohol
bit forms the prefix of the name and the carboxylic
acid the suffix so the name becomes eg alkyl
...oate. so ethanol
becomes ethyl and ethanoic acid becomes
ethanoate giving ethyl ethanoate.
-
Polyesters will now be covered in unit DP "Polymers by
Design"
-
Esters from phenols:
Phenols are not as reactive as alcohols in esterification reactions
and a more vigorous reagent is needed than refluxing it with an acid
catalyst. When an ethanoate is made the
process is called ethanoylation and there are two ethanoylating
reagents (or acylating reagents, meaning they replace the H of
the OH with an R-C=O group). Water must not be present in the reaction
mixture.
-
Ethanoic anhydride
(needed to understand preparation of aspirin in Act WM 5.1):
This is an example of an acid or acyl anhydride made by
eliminating a water molecule between two of the acid molecules. It
readily reacts with phenols (and alcohols!) to give the ester eg
aspirin preparation top of p319. The mixture is heated under
reflux and the ester and one molecule of ethanoic acid are formed.
-
Ethanoyl chloride
(most important to know for the exam): This is an example
of an acid or acyl chloride where the OH of the carboxylic
acid is replaced with a chlorine atom. They are reactive reagents with
phenols (and even more so with alcohols) even at room temperature.
Nasty acrid fumes of HCl are formed.
-
Ester
hydrolysis will now be covered in unit DP " Polymers by
Design"
Activity
WM3 "Investigating the chemistry of the -OH group in various environments"
-
All
the background chemistry is covered in Chemical Ideas 13.4 part b.
-
You need to know the results of
testing ethanol, phenol, ethanoic acid and 2-hydroxybenzoic acid with (i)
universal indicator, (ii) sodium carbonate solution and (iii) iron(III)
chloride solution. Might be a good idea to do aspirin as well.
-
You
should know the simple tests for a
-
The questions are also good
revision.
Chemical
Storylines
WM4 "INSTRUMENTAL ANALYSIS"
Chemical
Ideas 6.4 "Infrared spectroscopy"
-
When
electromagnetic radiation interacts with matter there can be changes
in electronic, vibrational or rotational energy levels, ie energy
absorbed to raise something to a higher quantum level.
-
Infrared
radiation causes changes in vibrational levels, that is the rate of
oscillation of usually two or three atoms in a molecule in a particular 'vibrational
mode' eg symmetric/asymmetric stretching or bending modes (see Figs 12, 13
and 15).
-
These
frequencies of vibration are quantised and each set of atoms involved in a
particular vibrational mode has its own characteristic frequency. So if
radiation of the 'right energy' is passed through a substance, that is the
radiation frequency matches the frequency of a vibration level, energy is
absorbed.
-
When
a substance is 'scanned' with a range of infrared frequencies,
characteristic absorption patterns are produced, and this 'finger print' is
called the infrared absorption spectrum (Fig 14).
-
The
absorption is registered as a reduction in the % transmittance to
produce a series of 'troughs' in the spectrum.
-
The
frequencies are expressed in infrared data/spectra as their wavenumber
in cm-1 (that is the reciprocal of the wavelength in cm, it
just gives a reasonable range of numbers to deal with eg usually 700 - 4000
cm-1)
-
Particular
groups of atoms have quite well defined, and characteristic absorption
wavenumbers and so an infrared spectrum is an important
analytical tool in deducing molecular structure (see Fig 14, and
tables 3-4, p139-140)
-
Fig
16, p137, shows how an infrared spectrometer works.
-
The
infrared beam is split in two, one beam goes through the sample solution
(or salt disc containing compound).
-
The
second beam is for reference ie a 'blank', and goes through the pure
solvent (or pure salt disc).
-
The
difference between the two beams is what the sample actually absorbs.
-
The
frequency or wavenumber is varied by passing the resulting beams through
a rotated prism or diffraction grating.
-
Interpreting
the spectra to identify particular molecular structure features requires
problem solving experience, its the only way to learn it!, and you will given a table like Table
3, p139, in the exam data booklet.
-
Note
that the same group of vibrating atoms can have more than one
characteristic wavenumber
-
AND
the intensities of absorption can be quite variable eg strong S or
moderate M.
-
AND
some show up as sharp troughs (eg C=O, Fig 18, at 1630-1740 cm-1)
or cover a broader band of wavenumbers (eg O-H, Fig 19, at 3100-3500 cm-1)
Study
the examples on pages 138-141 and realise that there are limitations to its
use as a 'molecular investigative tool'.
-
For
but-1-ene you get C=C (1620-1680 cm-1) but most organic
molecules will have C-H!
-
For
propanone, similarly, all you get is C=O (1705-1725 cm-1), but
you can sometimes say its in a ketone or an amide.
-
For
ethanol you get C-O (1050-1300 cm-1) and O-H (3200-3640,
broadish in liquids due to hydrogen bonding).
-
For
butane you get little, but does clearly illustrate the point that
if a characteristic significant peak is missing, then the molecule
doesn't have that functional group!
-
For
methylbenzene you can get the benzene ring from particular
C-H vibrations at >3000 cm-1)
-
For
benzoic acid you can get O=H (sharp 3580 cm-1, not H bonded), C=O
(1760 cm-1) and C-H in aromatic ring (>3000 cm-1).
-
Generally
the infrared spectrum is used as a 'finger print' to identify a
molecule, its rarely used to identify functional groups,
except in helping to solve A level chemistry molecular structure
problems!
Chemical
Ideas 2.1 "A simple model of the atom" (revision)
-
Revision
of how a mass spectrometer works by separating particles of different mass
after converting them to positive ions, which follow different paths in a
magnetic field. By changing the magnetic field strength, ions of a
particular mass can be focused on a detector and their relative intensity
measured.
-
In
WM the idea is extended from ions from atoms to ions from whole molecules eg C6H5COOH+
(m = 122) or a fragment from such a molecule eg C6H5+
(m = 77) because the molecules break up when hit by the electrons from the
-ve source.
Chemical
Ideas
6.5 "Mass spectrometry"
-
The
mass spectrometer is another tool for deducing molecular structure (a few
details of revision above).
-
In
mass spectrometer, a molecule is initially converted into its molecular
ion M+, this is the whole molecule just stripped of one
electron. Its detection is useful for providing the molecular mass Mr
of the compound.
-
However
this is unstable and breaks down under further electron bombardment into
smaller pieces in a process called fragmentation.
-
Any
fragment that forms a positive ion can be detected, and when the intensity
of each ion is measured by the detector, it was possible to produce the
whole fragmentation pattern (and molecular ion peak) in the form of a mass
spectrum:
-
this
is a chart of relative ion peak intensity versus mass, the intensity is
the relative amount of the ion of that mass
-
quite
often the tallest peak, for the most abundant ion, is called the base
peak, is given the value of 100% as an arbitrary value,
against which the other peaks are measured.
-
the spectra can be quite
complicated to interpret because of the 'strange' chemistry of the
unstable fragments, however for each compound there is a 'finger
print' pattern which can be used to identify a compound
-
AND particular
fragments, of particular mass, can be identified as particular molecular
structure feature (see Fig 28, p143 and table 5 p144).
-
however it is rare to
completely deduce the whole molecular structure, but it can help to
distinguish between two different compounds of different molecular
formula and even structural isomers.
-
It is possible to
distinguish between two different molecular formula with the same value
of Mr+, when the molecular ion peak is very
accurately measured (see Q7).
-
The presence of isotopes
is another complication in interpreting mass spectra.
-
For chlorine compounds,
any fragment containing a Cl atom, gives double peaks with a
difference of two mass units, due to the 35Cl and 37Cl
isotopes and there is a 'tell tale' ratio of the 'twin peaks' is 3:1
because of their relative isotopic abundance.
-
For bromo compounds
there will be similar twin peaks, 2 mass units apart, but of equal
height, due to a 1:1 ratio in naturally occurring bromine of 79Br:81Br
-
For the exam I would
not worry about using the 12C to 13C fragment
ratio to deduce molecular formulae or number of C atoms in the
molecule, but be aware that as the C number increases, there is a
greater chance of seeing a small peak at 1 mass unit higher than the
main molecular ion peak.
-
Interpreting
the spectra to identify particular molecular structure features and deduce
the molecular structure requires
a problem solving experience, its the only way to learn it!
Activity
WM4 "Interpretation of the mass spectrum of salicylic acid"
-
The
exam Q's on mass spectroscopy will not be this demanding, but the ideas of
the molecular ion peak [M]+, [M+1]+ peak due to 13C,
prominent fragment ions and finger print patterns are all important (see
Chemical Ideas 6.5 above).
Chemical
Storylines WM5 "THE SYNTHESIS OF SALICYLIC ACID"
-
When
a 'complex' natural compound's structure is known, and it, or a modification
of it, proves a useful compound, the search begins for molecules to
synthesise it from (Assignment 3).
-
Compounds
similar in structure to the 'lead' molecule from nature are synthesised and
tested for pharmacological properties (on people!). This is what Hoffmann
did, and came up with 'Aspirin'.
-
It
is possible to combine phenol with carbon dioxide to synthesise
2-hydroxybenzoic acid. This is reacted with ethanoic anhydride to make
2-ethanoylhydroxybenzoic acid (Aspirin). Its not very soluble in water and
was eventually sold in 'tablet' form.
-
'HISTORIC'
NOTE: Before the days of modern instrumental techniques, the only real way
to prove the structure of a molecule, was to synthesise it with well-known
chemistry, and when the 'known' synthesised compound's properties matched
the original molecule, you'd cracked it!
Activity
WM5.1 "A preparation of aspirin"
-
You
should be able to outline the general method of preparation ...
-
be
able to describe reduced pressure (vacuum) filtration, wash out
some of the impurities with a little iced water
-
be
able to describe recrystallisation - dissolve crude product in
minimum hot solvent (water), allow to cool to reform purer crystals
(hopefully, the impurities stay in solvent), re-filter, collect onto
clean watch glass and leave to dry.
-
write the reaction equation
-
calculate
a % yield, ie the % actually obtained of the maximum possible as
calculated from a theoretical reactant and product masses.
-
Note
the methods of testing for impurities, the most prominent being the
original 2-hydroxybenzoic acid.
-
neutral
iron(III) chloride solution - phenol group (not present in aspirin)
-
thin-layer
chromatography, one spot only if pure?
-
melting
point, sharp narrow range eg 138-140 if aspirin pure, lower wider
melting range if impure
Activity
WM5.2 "Using spectroscopy"
Chemical
Storylines WM6
"DELIVERING THE PRODUCT"
-
It
costs a lot of money to develop a new medicine so the price charged by the
pharmaceutical company must cover the cost of research, production and
marketing.
-
Patents
are taken out to protect the company's commercial interests in the new
medicine.
-
There
can be a range of formulations of a particular medicine when you buy it over
the counter eg tablet of 100% aspirin, soluble aspirin (via Na+
salt of the acid from neutralisation) and aspirin might form part of a
mixture including substances that have other beneficial effects.
Activity WM6
"An aspirin assay"
-
Be able to describe the
basic method: weighing out aspirin, dissolve in ethanol (because aspirin
not very soluble in water), titrate with standard sodium hydroxide using
phenolphthalein (end-point is first permanent pink).
-
Assay
calculation: If a 300mg aspirin tablet dissolved in ethanol required
16.5 cm3 of 0.1M NaOH for neutralisation. If you get 99.1%, you
know how to do em'! (or tell me I'm wrong!, 1st WM edition is being
rushed!!!!!)
Chemical
Storylines WM7
"THE MIRACULOUS MEDICINE"
-
The
main point here is that aspirin, like many drugs, can have multi-functional
effects, hopefully all beneficial.
-
BUT
this, sadly, is not always the case, because with any new drug there is
always the danger of unknown side-effects.
-
Therefore
there is a tremendous responsibility on pharmaceutical companies to ensure
the development of safe and effective drugs ... which leads into Storylines
WM8
Storylines
WM8 "DEVELOPING AND SAFETY TESTING OF MEDICINES"
Activity
WM8 "Which product should a pharmaceutical company develop?"
This page should cover all of: WM9 SUMMARY,
WM9 Check your notes on "What's in a Medicine" and the WM
learning objective list to prepare you for the WM Unit Test and
hence the module examination 2851.
GENERAL
REVISION
NOTES

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