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INORGANIC
Part 10 3d block TRANSITION METALS sub-index: 10.1-10.2
Introduction 3d-block Transition Metals * 10.3
Scandium
* 10.4 Titanium * 10.5
Vanadium * 10.6 Chromium
* 10.7 Manganese * 10.8
Iron * 10.9 Cobalt
* 10.10 Nickel
* 10.11 Copper * 10.12
Zinc
* 10.13 Other Transition Metals e.g. Ag and Pt * Appendix 1.
Hydrated salts, acidity of
hexa-aqua ions * Appendix 2. Complexes
& ligands * Appendix 3. Complexes and isomerism * Appendix 4.
Electron configuration & colour theory *
Appendix 5. Redox
equations, feasibility, Eø * Appendix 6.
Catalysis * Appendix 7.
Redox
equations
* Appendix 8. Stability Constants and entropy
changes *
Appendix 9. Colorimetric analysis
and complex ion formula * Appendix 10 3d block - extended data
* Appendix 11 Some 3d-block compounds, complexes, oxidation states
& electrode potentials * Appendix 12
Hydroxide complex precipitate 'pictures',
formulae and equations
Advanced
Level Inorganic Chemistry Periodic Table Index *
Part 1
Periodic Table history
* Part 2
Electron configurations, spectroscopy,
hydrogen spectrum,
ionisation energies *
Part 3
Period 1 survey H to He *
Part 4
Period 2 survey Li to Ne * Part
5 Period 3 survey Na to Ar *
Part 6
Period 4 survey K to Kr and important trends down a
group *
Part 7
s-block Groups 1/2 Alkali Metals/Alkaline Earth Metals *
Part 8
p-block Groups 3/13 to 0/18 *
Part 9
Group 7/17 The Halogens *
Part 10
3d block elements & Transition Metal Series
*
Part 11
Group & Series data & periodicity plots * All
11 Parts have
their own sub-indexes near the top of the pages
10.6. Chemistry
of Chromium
Cr, Z=24,
1s22s22p63s23p63d54s1
-
Cr
data table 1 summary *
extended chromium data table 2 *
Chromium & electrode potential
chart of 3d-block
-
Summary of some
complexes-compounds & oxidation states of chromium compared to other
3d-block elements
-
Chromium is a hard
white metal that is extremely resistant to chemical attack at room
temperature. It is used in the production of extremely hard steel
alloys e.g. ball bearings and coating steel articles for corrosion
protection ('chrome plating') and chromium metal is an important
component in 'stainless steel'.
-
Extraction of
chromium
-
Chromium
ore is processed and purified into chromium(III) oxide. This is reacted, very exothermically, in a thermit style reaction, with
aluminium (see reactions
of aluminium) to free the chromium metal.
-
Cr2O3(s)
+ 2Al(s) ==> Al2O3(s) + 2Cr(s)
-
The
chromium(III) oxide is reduced to chromium by O loss, the
aluminium is oxidised to aluminium oxide by O gain, and the
aluminium is the reducing agent i.e. the O remover.
-
These are examples of metal
displacement reactions e.g. the less reactive chromium or titanium
are displaced by the more reactive sodium, magnesium or aluminium.

CHROMIUM(III) chemistry
-
Chromium forms the stable
green (greyish green almost violet sometimes?) chromium(III) ion, [Cr(H2O)6]3+(aq).
-
With aqueous ammonia
(alkaline)
or sodium hydroxide colour green chromium(III) hydroxide is precipitated.
-
Cr3+(aq)
+ 3OH-(aq) ==> Cr(OH)3(s) (but
the structures can be quite complex)
-
or
[Cr(H2O)6]3+(aq)
+ 3OH-(aq) ==> [Cr(OH)3(H2O)3](s)
+ 3H2O(l)
-
VIEW ppts. with OH-, NH3
and CO32-, & complexes,
if any, with
excess reagent.
-
With aqueous
sodium carbonate the
hydroxide ppt. is formed (as above) and
carbon dioxide because of the acidity of the hexaaquachromium(III)
ion (see Appendix 1.):
-
*initially 2[Cr(H2O)6]3+(aq)
+ CO32-(aq) ==>
2[Cr(H2O)5(OH)]2+(aq)
+ H2O(l) + CO2(g)
-
this process
of proton donation (deprotonation) continues until [Cr(OH)3(H2O)3](s) is formed
-
No Cr2(CO3)3
is formed because of the acid-base reaction above, due to
the acidity of the chromium(III) ion. Note the similarly
highly charged small ions
Al3+ and
Fe3+ behave in the same way.
-
*
the acidity of a the hexa-aquachromium(III) ion can be expressed
as ...
With excess sodium
hydroxide or ammonia, further complex ions are formed by ligand
replacement reactions:
-
[Cr(H2O)6]3+(aq) + 6OH-(aq) ==> [Cr(OH)6]3-(aq)
+ 6H2O(l)
(from original hexa-aqua ion)
-
[Cr(H2O)6]3+(aq) + 6NH3(aq) ==> [Cr(NH3)6]3+(aq) + 6H2O(l)
(from original hexa-aqua ion)
-
The uncharged
ligand molecules ammonia NH3 and water H2O are
similar in size and ligand exchange occurs without change in
co-ordination number. They all octahedral complexes with a
co-ordination number of 6.
-
Chromium(III)
complexes are extremely numerous and varied, including many examples of
isomerism.
(see Appendix
2 and
Appendix 3 for an introduction to complexes)
-
Ionisation
isomerism in
chromium(III) chloride
based on Cr3+, 3Cl- and
6H2O
-
[Cr(H2O)6]3+(Cl-)3 (violet or
grey-blue?)
-
[CrCl(H2O)5]2+(Cl-)2.H2O (pale
green)
-
[CrCl2(H2O)4]+
Cl-.2H2O (dark
green)
-
[CrCl3(H2O)3]0*.3H2O
? (brown?, this I found reference to on
a Russian site, doesn't seem to be in textbooks? *the
0 to signify an overall electrically neutral
complex can be omitted)
-
and this is not
all, the 3rd one down with two chloride ligands can exist as cis (1) or trans (2)
geometric isomers
(Z/E isomers) illustrated below, and also serve as models for representing
the other octahedral complexes which exhibit cis/trans or Z/E
isomerism.
-
-
With excess chloride
ion you get the formation of the tetrahedral
tetrachlorochromate(III) ion
-
You also get
geometrical cis/trans isomers (Z/E) with
tetraamminedichlorochromium(III) complexes.
-

-
A similar case of
isomerism occurs with the chromium(III) complexes with ammonia and
chloride ligands shown above. All the complex ions above have a
plane of symmetry and cannot exhibit optical isomerism.
-
Again, these are
all octahedral complexes with a coordination number of 6.
-
[Cr(H2NCH2CH2NH2)3]3+,
H2NCH2CH2NH2,
ethane-1,2-diamine (ethylenediamine), is often represented in
shorthand by en,
-
Both the hexa-aqua ions
of chromium(II) and chromium(III) readily complex with EDTA
-
[Cr(H2O)6]2+(aq)
+ EDTA4-(aq) ===> [Cr(EDTA)]2-(aq)
+ 6H2O(l)
-
[Cr(H2O)6]3+(aq)
+ EDTA4-(aq) ===> [Cr(EDTA)]-(aq)
+ 6H2O(l)
-
From the Kstab
values, you can see that the more highly charged Cr3+(aq)
ion complexes more strongly than the Cr2+(aq)
ion.
-
-

CHROMIUM(VI) chemistry
-
When hydrogen peroxide is
added to an alkaline chromium(III) solution, oxidation occurs to give
the yellow chromate(VI) ion
CrO42-
.
-
2Cr3+(aq)
+ 3H2O2(aq) + 10OH-(aq)
==> 2CrO42-(aq) + 8H2O(l)
-
Redox changes:
oxidation 2Cr(+3) ==> 2Cr(+6), reduction 6 O(-1) in 3H2O2
==> 6(-2) in 6 of the 8H2O, total of 6 'units' oxidation state
change.
-
Both H2O2
and Cr(VI) compounds are oxidising agents but in alkaline
solution H2O2 is the stronger oxidising
agent.
-
When the
resulting solution from above is acidified with dilute sulphuric
acid, the orange
dichromate(VI) ion
Cr2O72-
is formed.
-
The equilibrium is pH
dependent. From 'Le Chatelier's Principle':
-
in more acidic
solution, more H+, decrease
pH ==> more orange (net change L to R) or in
-
more alkaline, less H+
(removed by OH-), increase pH <= more
yellow (net change R to L).
-
2CrO42-(aq)
+ 2H+(aq)
Cr2O72-(aq) + H2O(l) (no change in ox. state)
-
The dichromate(VI) ion is
reduced in two stages by a zinc/dilute sulphuric acid mixture.
-
Cr(VI, +6) ==> Cr(III,
+3):
Cr2O72-(aq) + 14H+(aq)
+ 6e-
2Cr3+(aq) + 7H2O(l)
-
Cr(III, +3) ==> Cr(II,
+2):
Cr3+(aq) + e-
Cr2+(aq)
-
Note
the EØZn(s)/Zn2+(aq)
is -0.76V, so the reducing power of zinc is sufficient to
effect either of the two chromium oxidation state reduction changes.
-
The full redox
equations for the reactions which happen on the surface of the zinc
are:
-
Cr2O72-(aq) + 3Zn(s)
+ 14H+(aq)
2Cr3+(aq) + 3Zn2+(aq)
+ 7H2O(l)
-
2Cr3+(aq) + Zn(s)
2Cr2+(aq) + Zn2+(aq)
-
You will see
hydrogen formed as a by-product of the zinc-acid reaction but the
reductions take place on the surface of the zinc.
-
Potassium
dichromate(VI), K2Cr2O7,
can be crystallised to high purity standard without water of
crystallisation, and is a valuable 'standard' redox volumetric reagent.
-
E.g. It can used to titrate iron(II) ions in
solution acidified with dilute sulphuric acid, using a redox
indicator like barium diphenylamine sulphonate which is less
readily oxidised than iron(II) ions, but once all the iron(II)
ions are oxidised
the indicator is oxidised to a blue colour. The iron(III) ions
formed affect the indicator to give an inaccurate end point so phosphoric(V)
acid is also added at the start to complex the Fe3+
ions as they form.
-
Cr2O72-(aq) + 14H+(aq) + 6Fe2+(aq)
==> 2Cr3+(aq) + 6Fe3+(aq) + 7H2O(l)
-
See also fully worked
examples of
redox
volumetric titration calculation questions.
-
The
dichromate(VI) ion is a strong oxidising agent - examples of
oxidising action: -
See above for
oxidation of iron(II) ions.
-
It oxidises
iodide ions to iodine.
-
Cr2O72-(aq) + 14H+(aq)
+ 6I-(aq) ==> 2Cr3+(aq) + 3I2(aq) + 7H2O(l)
-
The released iodine
can be titrated with standard sodium thiosulphate solution using starch
indicator.
-
2S2O32-(aq) + I2(aq) ==>
S4O62-(aq) + 2I-(aq) (black/brown
==> colourless endpoint)
-
This reaction
between the released iodine and sodium thiosulfate can be used to
estimate oxidising agents like dichromate(VI) ions. The iodine is
titrated with standardised sodium thiosulphate (e.g. 0.10 mol dm-3)
using a few drops of starch solution as an indicator. Iodine gives a
blue colour with starch, so, the end-point is very sharp change from the
last hint of blue to colourless.
Soluble
chromate(VI)
salts give yellow solutions, but lead(II) ions give a
yellow ppt. of lead(II) chromate(VI) and silver ions a dark red ppt.
of silver chromate(VI).
Pb2+(aq)
+ CrO42-(aq) ==> PbCrO4(s)
and
2Ag+(aq) + CrO42-(aq)
==> Ag2CrO4(s)
-
A few
drops of silver chromate is used as an indicator when
titrating chloride solutions with silver nitrate solution in
neutral solution. The solubility product for the white ppt. of
silver chloride
-
Ksp = [Ag+(aq)][Cl-(aq)]
= 2 x 10-10
mole2dm-6
-
is exceeded before the
solubility product of silver chromate(VI)
-
Ksp
= [Ag+(aq)]2[CrO42-(aq)]
= 3 x 10-12
mole3dm-9, until all the chloride is precipitated. The next drop of silver
nitrate causes the precipitation of brownish-red silver chromate, so the end point
is the formation of the dark red ppt
-
CHROMIUM(II) chemistry:
The
blue
hexaaquachromium(II) ion, [Cr(H2O)6]2+(aq),
can be formed by reducing chromium(III) salt solutions with
zinc and hydrochloric acid but it is rapidly oxidised back to
green chromium(III) ions by dissolved oxygen unless protected by
an inert atmosphere.V3+/V2+ EØ
= -0.26V, O2+H+/H2O EØ =
+1.23V , see Redox Electrode
Potential Chart
Scandium
* Titanium * Vanadium
* Chromium
* Manganese * Iron * Cobalt
* Nickel
* Copper *
Zinc
* Silver & Platinum
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