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GCE-AS-A2-IB Advanced Level Theoretical-Physical Chemistry revision notes
Equilibria Part 8
"Phase equilibria - vapour pressure, boiling point and intermolecular forces"
GCSE
Notes on reversible reactions-equilibrium *
Advanced Part 1. Equilibrium,
Le Chatelier's Principle-rules * Part 2. Kc and Kp equilibrium expressions and
calculations * Part 3.
Equilibria and industrial processes * Part 4.
Partition,
solubility product and ion-exchange * Part 5.
pH, weak-strong acid-base theory and
calculations * Part 6. Salt hydrolysis,
Acid-base titrations-indicators, pH curves and buffers *
Part 7. Redox equilibria, half-cell electrode potentials,
electrolysis and electrochemical series *
Part 8 sub-index: 8.1 Phase equilibria-vapour
pressure, boiling point and intermolecular forces (note Partition between two phases is in
Equilibria Part 4.1)
*
The K and ΔS-ΔG connection with EØcell
will be dealt with via new thermodynamics pages later, but an
example of a ΔS-ΔG calculation is given at the end of
the advanced kinetics pages and ΔG for cells is
mentioned in Equilibria Part 7.
M = old fashioned shorthand for mol dm-3
*
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query?comment
8.1
Phase equilibria
- vapour pressure
- e.g. liquid water
water
vapour or H2O(l)
H2O(g)
- The co-existence of water in two
different phases is a clear example.
- If water (or an aqueous
solution) is poured into a dry bottle and then stoppered, some of the
water will then evaporate to create a vapour pressure, so water vapour
and liquid water co-exist.
- However, some of the water
vapour may condense if the gas molecules hit the liquid surface.
- When the rate of evaporation = rate
of condensation, a dynamic physical equilibrium exists between
liquid water and water vapour.
- Note, that at a certain temperature and
pressure (called the triple point), liquid water, water vapour and ice can all
co-exist!
- The maximum or saturated
vapour pressure that liquid water exerts at a particular
temperature can be measured and it increases exponentially with increase in
temperature, i.e. the equilibrium is shifted more to the right, see graph
below.
- The same shaped graph line
(examples below) is obtained with any liquid, though the relative
position of the curve depends on the volatility of the liquid, which
in turn depends on the strength of the inter-molecular attractive
forces (see later paragraph).
-
Typical
saturated vapour pressure curves
(max. pvap versus temperature).
- The vapour pressure curves for
tetrachloromethane CCl4, ethanol C2H5OH,
benzene C6H6, water H2O
and ethanoic acid CH3COOH.
- The increase in
vapour pressure of any liquid with rise in temperature is due to the
increasing average kinetic energy of the liquid molecules, so more
molecules with sufficient KE can 'escape' the intermolecular attractive forces of the
liquid molecules, increasing the rate of evaporation.
- When the vapour pressure of a
liquid matches the ambient pressure, the liquid boils as bubbles of
vapour can now form in the bulk liquid.
- At 100oC,
water vapour pressure = normal atmospheric pressure, and so water boils at
normal atmospheric pressure (1 atm/760 mmHg, see dotted lines on
diagram above).
- This has consequences for brewing a
cup of tea as you climb a high
mountain. It gets more and more difficult to brew a good pot of tea
because the boiling temperature gets lower and lower as the pressure
falls with increasing height.
- The greater the
intermolecular forces between molecules, the lower the saturated
(maximum pvap) vapour pressure at a given
temperature, here given in Pa/mm Hg 20oC.
- You also see, not
surprisingly, a corresponding higher enthalpy of vaporisation (ΔHvap/kJ
mol-1) and higher boiling point (bpt at 101325Pa/1
atm/760 mmHg) as more kinetic energy is needed by the molecules to
overcome the intermolecular attractive forces.
- e.g. compare five liquids
of similar molecular mass and total number of electrons whose physical
properties illustrate these trends.
- ALKANE
butane, CH3CH2CH2CH3 ,
Mr = 58, 34 electrons,
- bpt -0.5oC, ΔHvap
= 22 kJ mol-1, sat'd pvap = 211316 Pa/1585
mmHg at 20oC when liquified under pressure.
- A non-polar molecule where
the only intermolecular force operating is the weakest possible,
that is the instantaneous dipole - induced dipole
intermolecular forces
(Van der Waals forces).
- Van der Waals electrical
attractive forces act between
ANY molecules and is primarily a function of the number of
electrons in the molecule. The force arises from the instantaneous and
random asymmetry of the electron fields in the atomic orbitals. A
transient d+ in one molecule induces a transient
d- in a neighbouring molecule, so
causing a very weak and transient attraction.
- This is why, in
doing comparisons, you should choose molecules of similar molecular
mass and total electron number to give a 'base-line' of similar
effects of Van der Waals forces, from which you can then judge the
effects of changing molecular structure e.g. polar bonds
increasing the inter-molecular attractive forces between polar
molecules.
- In examples 1 to 5, the
molecules exhibit extra intermolecular forces due to polar bonds,
and in the description it is assumed you are aware that
instantaneous dipole - induced dipole are ever present.
- HALOGENOALKANE
chloroethane, CH3CH2Cl ,
Mr = 64.5,
34 electrons,
- bpt 12.5oC, ΔHvap = 25 kJ
mol-1, sat'd pvap = 133322 Pa/1000 mmHg
at 20oC when liquified under pressure,
- Halogenoalkanes have a
weakly polar Cd+-Xd- bond (X = halogen) due to the
difference in electronegativities (Pauling values) of carbon and
halogens, e.g. Cl(3.0) > C(2.5) giving Cd+-Cld-.
- This gives rise to a weak,
but permanent dipole, hence the extra permanent dipole -
permanent dipole intermolecular attractive forces raising the bpt and ΔHvap
and lowering the vapour pressure compared to butane.
- KETONE
propanone, CH3COCH3 ,
Mr = 58, 32 electrons,
- bpt 56oC, ΔHvap
= 29 kJ mol-1, sat'd pvap = 24131 Pa/181
mmHg at 20oC,
- Ketones are permanently polarised
molecule due to the highly polar bond
d+C=Od- caused by the difference in
electronegativities of carbon and oxygen i.e. O(3.5) > C(2.5).
- This causes the permanent dipole - permanent
dipole interaction between neighbouring polar molecules via ....d+C=Od-....d+C=Od-.... The vapour
pressure is reduced, and the bpt. and ΔHvap increased
compared to butane because there is a 2nd intermolecular force
operating.
- The effect is also greater than for
chloroethane because the electronegativity difference between C
and O is greater than C and Cl, giving a more polar molecule, so
stronger permanent dipole - permanent dipole intermolecular
attractive forces.
- ALCOHOL
propan-1-ol, CH3CH2CH2OH ,
Mr = 60, 34 electrons,
- bpt 97oC, ΔHvap = 45 kJ
mol-1, sat'd pvap = 1933 Pa/14.5 mmHg at 20oC,
- Alcohols are permanently polarised
molecule due to the highly polar bond
d-O-Hd+ caused by the difference in
electronegativities between oxygen and hydrogen i.e. O(3.5) >
H(2.1). This causes the extra permanent dipole - permanent
dipole interaction between neighbouring polar molecules via hydrogen bonding
- ....d-O-Hd+....d-O-Hd+....d-O-Hd+....
- So called hydrogen bonding
is the strongest of the permanent dipole - permanent dipole
intermolecular forces, but it is NOT a true ionic or covalent
chemical bond.
- The vapour
pressure is reduced, and the bpt. and ΔHvap
considerably increased
compared to butane because of this 2nd intermolecular force
operating. The effect is also greater than for
chloroethane/propanone for two reasons, (i) the electronegativity
difference between O and H is greater than for C and Cl or C
and O giving a more polar bond, and (ii) the small size of the
hydrogen atom of one molecule allows it to get nearer to the
oxygen of a neighbouring molecule increasing the strength of this
particular intermolecular force.
- CARBOXYLIC ACID
ethanoic acid, CH3COOH ,
Mr = 60, 32 electrons,
- bpt 118oC, ΔHvap = 58
kJ mol-1, sat'd pvap = 1520 Pa/11.4 mmHg at 20oC,
- Of the five compared
organic molecules, ethanoic acid has the highest bpt and ΔHvap
and lowest vapour pressure at 20oC.
- This is because as well as
the Van der Waals forces (instantaneous dipole - induced dipole
attraction), there are two sources of permanent dipole - permanent
dipole interactions.
- Permanent dipole - permanent dipole
interaction between neighbouring polar molecules via the
carbonyl group ....d+C=Od-....d+C=Od-.... (see propanone above for
more details),
- and the even stronger hydrogen bonding
via the hydroxy group ....d-O-Hd+....d-O-Hd+.... (see propan-1-ol above for more
details).
- This makes ethanoic acid
the most polar of the molecules and exhibiting the strongest
intermolecular forces.
- for extra comparison:
- water, H2O,
Mr = 18, 10 electrons, bpt 100oC, ΔHvap =
41 kJ
mol-1, sat'd pvap = 2340 Pa/17.5 mmHg at 20oC,
- On the basis of molecular
mass and electron number (< 1/3rd of examples 1-5), the data shows
that the bpt and ΔHvap of water are much higher,
and the vapour pressure much lower than expected, even compared to
the polar molecules described above.
- This is due to water
exhibiting the strongest intermolecular force hydrogen-bonding ....d-O-Hd+....d-O-Hd+.... as in alcohols. BUT, the
two lone pairs on the oxygen and the two available hydrogens
attached to the oxygen mean that water can form twice as many
hydrogen bonds per molecule than alcohols.
(relative diagram to do)

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REVISION
NOTES

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