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Brown's Chemistry Clinic
Advanced
Level Inorganic Chemistry Revision notes
(e.g. UK Advanced Level Chemistry GCE-AS-A2-IB US K12 grades ~11-12)
The
Periodic Table Part 10
Part
10c "3d block - Transition Metals"
revision notes
1st draft
10c: Appendices
1 to
9 (see
list below)
GCSE Chemistry
revision notes *
GCSE notes on Transition Metals *
Email
query?comment
Part 10 3d block sub-index:
1. Introduction * 2.
3d-block data, general trends and character of
Transition Metals
* 3. Scandium * 4. Titanium * 5.
Vanadium
* 6. Chromium * 7. Manganese * 8.
Iron
* 9. Cobalt 10. Nickel * 11.
Copper
* 12. Zinc * 13. Other Transition Metals
e.g. silver Ag or platinum Pt * Appendix 1. Acidity
of hexa-aqua ions * Appendix 2. Complexes &
ligands - the basics * Appendix 3. The shapes of complexes and isomerism
*
Appendix 4. Electron configuration and colour theory
* Appendix 5. Redox equations, feasibility, calculating Eøreaction
* Appendix 6. Catalysis - examples and theory * Appendix 7. Balancing
redox equations * Appendix 8. Stability
Constants of complex ions *
Appendix 9. Colorimetry - quantitative analysis and determining
the formula of a complex ion * Appendix 10. Preparation of
complexes * Extra
3d block - Transition Metals
data * Extra Hydroxide precipitate 'pictures'
* Extra comparison of 3d-block formulae and
oxidation states
* Extra Electrode Potential Chart for
3d-block
Advanced Periodic Table Index *
Part 1
A brief Periodic Table history *
the modern Periodic Table
* Part 2
Electronic structure of atoms :
Spectroscopy and the H spectrum :
Ionisation energies *
Part 3
Period 1 survey : 1. Hydrogen
:
2. Helium : Summary of
Period 1 : heavier element
formation-stellar nuclear fusion *
Part 7
s-block metals Groups 1/2 Alkali/alkaline Earth Metals *
Part 11
Group and Series data summaries
and links to periodicity plots
Quick
click to
Introduction *
Sc * Ti
* V * Cr *
Mn
* Fe * Co * Ni
* Cu * Zn * Ag/Pt etc.
10c Appendix
1. Hydrated
salts, metal-aqua
complex ions and their relative
acidity
(not necessarily just
transition metal ions)
-
All metal ions in
solution are 'associated' with water. The water molecules can also be
weakly bonded or more strongly as a ligand to form a complex
ion, and these can also present in solid 'hydrated' salts on
crystallisation e.g.
-
FeSO4.7H2O(s),
CoCl2.6H2O(s), CuSO4.5H2O(s)
etc.
-
Iron(II)
sulphate heptahydrate, cobalt(II) chloride hexahydrate and
copper(II) sulphate pentahydrate.
-
The above
crystals contain 7, 6 and 5 molecules of water of crystallisation
respectively.
-
A hexa-aqua ion
is present in the first two, [M(H2O6)]2+
(M = Fe, Co)
-
In the case of
copper(II) sulphate, 4 water molecules are covalently bonded to form a square
planar complex ion, [Cu(H2O)4]2+
and the 5th water molecule is hydrogen bonded to this ion and a
neighbouring sulphate ion helping to hold the crystal lattice
together.
-
However,
this blue crystal lattice is readily broken down on heating, a
classical demonstration of a reversible reaction, since the
white anhydrous solid turns blue on adding water (a simple
test for water.
-
CuSO4.5H2O(s)
CuSO4(s) + 5H2O(g/l)
-
Lewis acid-base theory:
-
A base is an electron pair donor and an
acid is an electron pair
acceptor.
-
Ligands like
water, can donate a pair of non-bonding electrons (lone pair) into a
vacant orbital of a central metal ion and so dative covalent
(co-ordinate) bonds
hold a complex together.
-
The central metal
ion with vacant bonding orbitals can act as a Lewis acid.
-
Ligands act as Lewis
bases by electron pair donation to form the metal-ligand bond.
-
Bronsted-Lowry
acid-base theory (essentially a sub-set of Lewis Theory)
-
Many hexa-aqa complex ions can
undergo acid-base reactions with water to produce solutions of pH less
than 7.
-
Usually group
2, 3 and transition metal ions.
-
The positive central
metal ion polarises a water molecule, releasing a proton, H+.
-
In the
deprotonation reaction the proton
transfers to water and the overall charge on the complex falls by 1
unit since the H2O - H+ = OH-,
i.e. one of the ligands is now a hydroxide ion.
-
In these
reactions the hydrated ions act as
Bronsted Lowry acids and
water
acts as a Bronsted-Lowry base.
-
e.g. [M(H2O)6]2+(aq)
+ H2O(l)
[M(H2O)5(OH)]+(aq)
+ H3O+(aq)
-
e.g. when M = Mn, Fe,
Co, Ni, Cu, Mg etc. give very weak acid solutions with
pH's just less than 7.
-
Ti(II), V(II)
and Cr(II) M2+ ions are redox unstable in the presence of air, but
theoretically their salts give very weakly acid solutions, but,
since they are usually prepared by zinc-acid reduction from higher
oxidation states, its not a very relevant fact here.
-
e.g. [M(H2O)6]3+(aq)
+ H2O(l)
[M(H2O)5(OH)]2+(aq)
+ H3O+(aq)
-
e.g. when M = Ti, V,
Cr, Fe, Al etc. give very weak acids solutions (but generally
stronger than for M2+) of pH's in the 3-5 region.
-
In the
presence of alkali, OH-, removing H3O+
ions, the equilibrium moves more to the right and more
protons are lost from the complex in stages until the hydroxide
precipitate is formed e.g. for iron(III), chromium(III) or
aluminium.
-
Some of the M3+
hydroxides are amphoteric and dissolve in excess alkali
(1.) or acid (2.) e.g. to eventually form for iron(III) or
aluminium, 1. the soluble hexa-hydroxo complex ion or 2. the
original hexa-aqua ion.
-
[M(H2O)3(OH)3]0(aq)
+ 3OH-(aq)
[M(OH)6]3-(aq)+
3H2O(l)
-
[M(H2O)3(OH)3]0(aq)
+ 3H3O+(aq)
[M(H2O)6]3+(aq)
+ 3H2O(l)
-
As a general rule
the greater the
polarising power of the central metal ion, the lower the pH of the resulting aqueous solution, i.e.
the acid-base equilibrium is shifted more to the right causing an
increase in acidity of the solution.
-
This effect
and process facilitated by the central metal ion on one
water ligand molecule can be envisaged as
-
[M-O-H2]n+
==> [M-O-H]n+-1 + H+ (proton transferred to a water
molecule)
-
One of the O-H
bond pairs is 'attracted' onto the oxygen atom by the electric field
effect of the central metal ion of charge n+, allowing proton
transfer to the base water.
-
Polarising
power is a function of ionic charge/ionic radius ratio.
therefore ...
-
the greater the metal
ion charge (n+), the more acidic the solution,
-
and the smaller the
radius of the metal ion, the more acidic the solution, so ...
-
both
increasing charge, or decreasing the central cation radius intensify the electric
field polarising effect on a water
ligand.
-
The acidity of the
hexaaquions
M3+(aq) due to the polarising influence of the
central highly charged M3+ ion accounts for the lack of
stability/existence of e.g. aluminium carbonate, iron(III)
carbonate or chromium(III) carbonate, whereas MgCO3 , ZnCO3 and FeCO3
etc. with the less polarising M2+ ion exist. It
also accounts for why you see bubbles of carbon dioxide when
carbonates/hydrogencarbonates are mixed with aluminium chloride, iron(III) chloride or chromium(III) chloride solutions e.g.
-
2[Fe(H2O)6]3+(aq)
+ CO32-(aq)
2[Fe(H2O)5(OH)]2+(aq)
+ H2O(l) + CO2(g)
-
or [M(H2O)6]3+(aq)
+ HCO3-(aq)
[M(H2O)5(OH)]2+(aq)
+ H2O(l) + CO2(g)
-
There several
legitimate permutations based on these equations.
-
-
Quick
click to
Introduction *
Sc * Ti
* V * Cr *
Mn
* Fe * Co *
Ni
* Cu * Zn *
Ag/Pt etc.
10c Appendix
2.
Complexes - introduction:
ligands, bonding, co-ordination number and charge on complex ions
-
A complex is
formed by the combination of a central
metal ion surrounded by, and bonded to, neutral molecules or ions
acting as 'ligands' (bits stuck on or appendages).
-
A
ligand
is an
atom, ion
or molecule which can act as an electron pair donor (Lewis base) and usually
forms a dative covalent or 'co-ordinate' bond with the central
metal ion.
-
The lone pair
donation is usually from an O, N or halogen atom of the ligand
in this covalent co-ordinate bonding.
-
The central metal
ion acts as a Lewis Acid, that is, an electron pair
acceptor from the ligand by way of vacant 3d, 4s, 4p and even 4d
orbitals for the 3d-block transition elements.
-
The ligand acts as
a Lewis Base, that is, an electron pair donor e.g.
neutral ligands like H2O: (water, aqua in
complex name) or :NH3 (ammonia, ammine in
complex name) and negatively charged ligands like :OH-
(hydroxide, hydroxo in complex name), Cl-
(chloride ion, chloro in complex name) and :CN-
(cyanide ion, cyano in complex name).
-
...
-
A an example of
the bonding in a complex ion is shown in the above diagram. The
negative cyanide ion is a monodentate ligand (forms one bond
per ligand) and donates an electron pair into a vacant 3d, 4s or 4p
orbital in the iron(III) ion to form six dative covalent bonds.
-
The resulting
ion has the formula [Fe(CN)6]3-, the
overall charge of 3- is the aggregate of 6- (cyanide ions) plus
3+ (iron ion)
-
The
co-ordination number of 6, which means there are 6 central metal
ion - ligand bonds. It doesn't necessarily mean six ligands, you can
get a co-ordination number of 6 from three co-ordinated bidentate
ligands (2 bonds per ligand), two tridentate ligands and from EDTA
just one ligand can form 6 dative covalent bonds with a central
metal ion. More on this below.
-
The ligand may attach
itself by one or more bonds. The suffix '...dentate',
prefixed by mono/uni/bi/ploy/multi e.g. monodentate (unidentate), bidentate, or
polydentate (multidentate)
is used to denote the number of bonds each ligand makes with the
central metal ion.
-
The total number of
ligand bonds to the central metal ion is called the co-ordination
number.
-
It is not the number
of ligands, unless it is a monodentate ligand.
-
There is no firm
rules relating shape to a particular ligand.
-
The six ligands
don't have to be the same e.g. ...
-
... which is the
dichlorotetraaquachromium(III) ion. This octahedral complex with a
co-ordination number of 6, and note this has an overall ion charge of (2
x - from 2Cl-) + (3+ from Cr3+) = +, water is an
electrically neutral ligand.
-
Examples of unidentate/monodentate
ligands:
-
e.g. neutral ligands:
water H2O:, ammonia :NH3, primary aliphatic
amines e.g. butylamine CH3CH2CH2CH2NH2,
-
These ligands
often form octahedral shaped
complexes with a co-ordination number of 6.
-
e.g. negative
ligands: chloride Cl-, cyanide CN-,
-
The chloride
ion Cl- forms the tetrahedral e.g. the
tetrachlorocuprate(II) complex ion ...
-
[CuCl4]2-,
note the overall charge is (2+) + (4 x -) = 2- and the
co-ordination number is 4.
-
The chloride ion
can be too bulky to form an
octahedral complex, though there is no firm rules relating shape to
ligand.
-
and CN-
square planar e.g.
the tetracyanonickelate(II) complex ion ...
-
[Ni(CN)4]2-,
note the overall charge is (2+) + (4 x -) = 2- and the
co-ordination number is 4.
-
Note that [Cu(H2O)4]2+,
the tetraaquacopper(II) ion, with the less bulky water molecule
ligand, forms a blue square planar complex, whereas with the larger
chloride ion, a tetrahedral complex is formed.
-
A linear shaped
complex is formed between a silver ion and ammonia.
-
[Ag(NH3)2]+
is formed in 'ammoniacal' silver nitrate solution used in the
test for aldehydes. The diamminesilver(I) ion has co-ordination
number of 2 and an overall charge of a single + because the
ammonia molecule is an electrically neutral ligand.
-
Examples of bidentate
('two toothed') ligands:
-
neutral ligands:
diamines like 1,2-diaminoethane (ethane-1,2-diamine) H2NCH2CH2NH2 (bonds
via lone pair :N).
-
negative ligands:
ethanedioate ion C2O42-, (bonds
via lone pair on the :O-). The L represents
where the dative covalent bond forms.
-
shows three bidentate ligands co-ordinated to a
central metal ion (co-ordination number 6, 'octahedral' in bond arrangement).
-
Examples:
[Cr(H2NCH2CH2NH2)3]3+,
H2NCH2CH2NH2 is
often represented in shorthand by en,
-
Bidentate
ligands are the first of what are called polydentate ligands and
such complexes are sometimes called chelates from the
Greek for 'crab's claw' and the complex formation described as a
chelation process.
-
More examples of
multi/polydentate ligands:
-
One ligand can replace
another depending on the relative bond strengths
in a reaction called ligand exchange reaction.
-
When a bidentate
or polydentate
ligand is added to a pre-existing complex of monodentate
ligands, it is highly likely
a more stable complex will be formed.
-
The principal reason
for this, (ignoring bond strengths), is the positive entropy
change accompanying the 'release' of 4 or 6 small molecules
which offer a greater variation of ways of arranging the particles
or energy
distribution.
-
If the ligands are easily
exchanged, the complex is described as 'unstable' and if the ligands
are more strongly bound, the complex would be described as stable.
-
Complex ion
stability is also related to the oxidation state of the
transition metal in the presence of a particular ligand.
-
See Appendix 3.
for more on complex ion shape and isomerism.
-
See Appendix 5.
for more on electrode potentials, oxidation state
and complex ion stability.
-
See Appendix 8.
for more on complex ion stability, entropy changes and stability equilibrium constants
(Kstab).
Quick
click to
Introduction *
Sc * Ti
* V * Cr *
Mn
* Fe * Co *
Ni
* Cu * Zn *
Ag/Pt etc.
10c Appendix
3. Complexes:
more on shapes and isomerism
-
Valence shell electron
pair repulsion theory
(VSEPR) can quite often be used to predict the
shape of a complex, which is usually one of
four shapes (at least at pre-university level):
-

-
Principal shapes:
-
Examples have been described in Appendix 2
-
For isomerism
analysis it crucial to the think of the orientation of the bonds and not
the number of ligands.
-
Octahedral
(co-ordination number 6): very common, geometrical and optical isomerism
possible.
-
Tetrahedral
(co-ordination number 4): with more bulky ligands like chloride ion,
optical isomerism possible.
-
Square planar
(co-ordination number 4): geometrical isomerism possible.
-
Linear
(co-ordination number 6): relatively rare and can't form isomers
-

-
Principal forms of
isomerism:
Quick
click to
Introduction *
Sc * Ti
* V * Cr *
Mn
* Fe * Co *
Ni
* Cu * Zn *
Ag/Pt etc.
10c Appendix
4. Electron
configurations and the theory and variation of complex ion colour
-
For the 3d-block know the
complete order of filling of the sub-shells from Z=21 to 30 and be
able to write out the full or abbreviated electron
configuration.
-
See under each
element and even more detail in
Electron Configurations in Periodic Table section 2.2.
-
The number of
orbitals per sub-shell, 1 for s, 3 for p, and 5 for d sub-shell.
-
PLEASE watch out for the two
‘quirks’ for Cr and Cu atoms and the order of
electron removal when forming positive ions e.g. for the 3d block of
transition metals, you remove the 4s electrons first, before any
of the 3d electrons.
-
Transition metals can be
identified by the colour of their complexes which of course is a
very characteristic feature of their chemistry (e.g. the
hydroxide precipitates which
are, of course, all neutral complexes).
-
The colour
can varies with
change in (i) oxidation state, (ii) ligand and (iii) co-ordination
number or shape (which in turn depends on the ligand and oxidation
sate).
-
All of these three
factors are linked to the electronic state of the central metal ion, so,
if the electronic levels are changed, the difference between quantum
levels changes, therefore the wavelength of the light photons absorbed
changes, i.e. the observed colour changes e.g.
-
e.g. (i) The
same ligand (H2O), shape and co-ordination number but
different oxidation state.
-
e.g. (ii) The
same oxidation state, shape and co-ordination number but
different ligand.
-
e.g. (iii) The
same oxidation state but with a different ligand, shape and
co-ordination number.
-
[Cu(H2O)6]2+,
blue hexaaquacopper(II) ion and [CuCl4]2-,
yellow tetrachlorocuprate(II) ion.
-
Same oxidation
state +2, but different ligands (water and chloride ion), different
shape (octahedral and tetrahedral) and different co-ordination
number (6 and 4).
-
COLOUR
THEORY for transition element complexes: The argument is
presented from the point of view of an octahedral complex, but
similar arguments apply for a tetrahedral or square planar
complex.
-
There are five 3d
sub-shell orbitals whose 3D spatial representations are shown
below. Theoretically it is considered that the ligands in an
octahedral complex approach the central metal ion along the x, y
and z axis, which would minimise the repulsion between the
orbitals of bonding electrons in the six M-ligand dative covalent bonds (note that
4s and 4p orbitals are involved in complex ion bonding).

The electronically excited states
of titanium(III) and copper(II) are illustrated below.
-
The colour arises from
electronic transitions from the ground state to excited states, the
energy needed can be calculated using
-
Planck's
Equation, ΔE = hv
, E = energy of a single photon (J), h
= Planck's Constant (6.63 x 10-34 JHz-1),
v = frequency (Hz).
-
Therefore if the
photo energy/frequency is equal to
ΔE
then energy is absorbed and an electron can be promoted from the
lower 3d level to the higher 3d level.
-
If
ΔE
is in the visible light frequency range the complex will be
'coloured'.
-
In the case
of coloured transition metal complexes, the colour arises from
visible light energy absorption on promoting electrons from the
lower 3d levels to the higher 3d levels.
-
However, this can only
occur if there is at least one electron in the 'lower' 3d orbitals and
at least one half-filled 'higher' 3d quantum level, i.e. the minimum pre-conditions for
an electronic transition or 'excitation'.
-
Consequently because
there a lack of such
possible transitions in Sc(III) and Zn(II) their compounds are usually
colourless i.e. no light absorbed in the visible region of the spectrum
-
In the true transition metals
from Ti to Cu,
it is possible for the electromagnetic radiation energy to produce this excitation from the lower to the higher
3d sub-levels and it is usually in the visible region. The frequencies of visible
radiation are absorbed and the perceived colour arises from the frequencies not
absorbed.
-
The electronic structure
and colour of some typical 'simple' aqueous ions is shown below. They
are all hexa-aqua ions of an octahedral shape except ...
-
The colour you see in a
transition metal compound is the visible light that isn't absorbed by
the 3d electronic transitions. For example, copper(II) complexes often
absorb in the red area of the visible spectrum, so the resulting
colour observed is green-blue.
-
Colour changes
in transition metal reactions can arise from change of ligand,
change in co-ordination number or change in metal oxidation state
(sometimes several of these simultaneously, see
cobalt(II) ion reactions with
ammonia + oxygen or chloride ion).
-
The colours are
quite useful for simple transition metal ion identification tests e.g.
precipitates with sodium hydroxide and ammonia (see pictures) and the
thiocyanate test for iron(III)
ions.
-
Ultraviolet and
visible absorption spectra
-
Dyes and pigments
-
Ultraviolet and visible
spectroscopy can be used to determine the concentration of metal
ions in solution, usually after the addition of a suitable ligand to
intensify the colour using the more elaborate technique of
spectrophotometry or the simpler technique of colorimetry
- appendix 9.
-
Theory: diagram,
spectra
-
Examples:
-
Colorimetric analysis of coloured solutions for quantitative analysis
using a colorimeter is described in Appendix 9.
Quick
click to
Introduction *
Sc * Ti
* V * Cr *
Mn
* Fe * Co *
Ni
* Cu * Zn *
Ag/Pt etc.
10c Appendix
5.
Eø Half-cell potentials/reactions, full redox equations and calculating
feasibility via Eøreaction
Database of Standard
Electrode Potentials,
Eø values
See also
the electrode potential chart
-
For those mentioned on
this web page for aqueous systems under standard conditions,
-
i.e. at 298K, 1 mol dm-3
concentration (aq), 1 atm. reactant gas pressure (if
appropriate),
-
and compared with the half-cell
potential for the standard hydrogen gas-hydrogen ion electrode
(via Pt electrode interface),
-
which is assigned the arbitrary convention value of
EøH+(aq)/H2(g)
= 0.00 V
-
2H+
(aq) + 2e-
H2 (g)
-
Details on
Part 7. Equilibria -
Redox systems (opens in new window)
-
Half-cell
electrode potential equations are usually quoted as a reduction
(as above and list below)
-
The
half-cell potentials are listed downwards from the strongest reducing
agent system (most negative
Eø/V) to the strongest oxidising agent system (the most
positive
Eø/V):
-
?
-
-0.76 for
Zn2+(aq) + 2e-
Zn(s) [Zn(II) ==>
Zn(0)]
-
-0.56 for
Fe(OH)3(s) + e-
Fe(OH)2(s) + OH-(aq) [Fe(III)
==> Fe(II),
in alkali]
-
-0.44 for
Fe2+(aq) + 2e-
Fe(s) [Fe(II) ==>
Fe(0)]
-
-0.41 for Cr3+(aq) + e-
Cr2+(aq) [Cr(III)
==> Cr(II), in acid]
-
-0.26 for V3+(aq) + e-
V2+(aq)
[V(III) ==> V(II), in acid]
-
-0.10 for [Co(NH3)6]3+(aq) + e-
[Co(NH3)6]2+(aq)
[Co(III) ==> Co(II) for NH3
ligand]
-
0.00
for 2H+(aq) + 2e-
H2(g) [the arbitrary assumed standard
value, H(+1) ==> (H(0)]
-
+0.34 for VO2+(aq) + 2H+(aq) + 2e-
V3+(aq) + H2O(l)
[V(IV) ==> V(III)]
-
+0.40 for
1/2O2(g) + H2O(l)
+ 2e- 2OH-(aq) [O(0)
==> O(-2),
in alkali]
-
+0.54 for
I2(aq) + 2e-
2I-(aq) [I(0)
==> I(-1)]
-
+0.77 for Fe3+(aq) + e-
Fe2+(aq)
[Fe(III) ==> Fe(II), in acid]
-
+1.00 for VO2+(aq) + 2H+(aq) + 2e-
VO2+(aq) + H2O(l)
[V(V) ==> V(IV) in acid]
-
+1.23 for
1/2O2(g) + 2H+(aq)
+ 2e-
H2O(l) [O(0)
==> O(-2),
in acid???]
-
+1.33 for
Cr2O72-(aq) + 14H+(aq)
+ 6e-
2Cr3+(aq) + 7H2O(l)
[Cr(VI) ==> Cr(III)]
-
+1.36 for
Cl2(aq) + 2e-
2Cl-(aq) [Cl(0)
==> Cl(-1)]
-
+1.51 for
MnO4-(aq) + 8H+(aq)
+ 5e-
Mn2+(aq) + 4H2O(l)
[Mn(VII) ==> Mn(II)]
-
+1.52 for Mn3+(aq) + e-
Mn2+(aq) + H2O(l)
[Mn(III) ==> Mn(II)]
-
+1.77 for
H2O2(aq) + 2H+(aq) + 2e-
2H2O(l) [O(-1)
==> O(-2),
in acid?]
-
+1.82 for Co3+(aq) + e-
Co2+(aq)
[Co(III) ==> Co(II) for H2O
ligand]
-
+2.01 for
S2O82-(aq) + 2e-
2SO42-(aq) [2O(-1) ==>
2O(-2)]
-
?
Calculation of
Eø for a redox reaction
-
In principle, any
accurately known half-cell potential can be used in a cell system to
obtain an unknown half-cell potential which can be used to
theoretically predict the feasibility of a reaction.
-
The electrochemical
series and electrode potential charts, know how to construct,
read and use them.
-
Other half-cells,
they don’t have to simple metal/ metal ions, all you need is two
interchangeable oxidation states eg Cl2(aq)/Cl-(aq)
or Mn2+(aq)/MnO4-(aq)
etc. but both components of the half-cell must be in the same solution
and in contact with a platinum electrode that connects to the rest of
the circuit (Fig 12 p213).
-
One way of working out Eø
values: Eøcell = Eø(red)
– Eø(ox)
(amounts to the difference between the half-cell potentials on an
electrode potential chart)
-
*
Eø(red)
is the most positive or the least negative = the
strongest oxidising agent or electron acceptor of the two
half-cell systems, and the +ve battery pole, eg Cu2+
compared to Zn2+, so Cu2+(aq)
+ 2e- ==> Cu(s), rather than
reduction of Zn2+,
-
and
Eø(ox)
is the least positive or the most negative = the
strongest reducing agent or electron donor of the two half-cell
potentials, and the -ve battery pole eg Zn
compared to Cu, so Zn(s) - 2e-
==> Zn2+(aq) happens rather
than oxidation of Cu,
-
overall cell redox
reaction: Cu2+(aq)
+ Zn(s) ==> Cu(s) +Zn2+(aq)
-
Calculating the
voltage-Emf for the copper-zinc cell:
-
Eø(red)
= EøCu(s)/Cu2+(aq) = +0.34V,
Eø(ox)
= EøZn(s)/Zn2+(aq) = -0.76V
-
Eøcell
= Eø(red) – Eø(ox)=
+0.34V - (-0.76) = + 1.10 V (feasible!)
For more details and examples
see
Equilibrium Part 7 Redox equilibria, half-cell electrode potentials,
electrolysis and electrochemical series
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Introduction *
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Ni
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10c Appendix
6. Catalysis
theory and practice
-
A catalyst is a
substance that alters the rate of chemical reaction without itself
being permanently chemically changed.
-
It will chemically change
temporarily e.g. change in ligand or oxidation state or other bonding
arrangement, but will return to is original state often via a 2-3
stage 'catalytic cycle'.
-
A catalyst provides a
reaction pathway with a lower activation energy Ea,
compared to the uncatalysed reaction (see diagrams immediately below, simple
exothermic/endothermic reaction and more realistically, a complex two
stage cycle profile further on).

Two primary modes
of catalytic action - heterogeneous and homogeneous

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10c Appendix
7. Balancing
redox equations
-
use of the correct
'species' (e.g. usually two given/chosen as/from half-cell equation
data)
-
the 'species'
direction change - which is oxidised or reduced? (if not indicated,
might have to decide from EØ data, the more +ve half-cell
gets reduced)
-
correct ratio of
half-cell equations - the 'balance' must be based on oxidation number
analysis, the total increase in oxidation states must be equal to the
total decrease in oxidation state
-
add up the ion
charges, the totals should be the same on both sides of the equation
(I find this a handy extra check especially with stray H+'s!)
-
'traditional' atom
count - placed last because its not completely reliable with redox
equations!
-
There are two
separate web pages with help and examples explained
Revision notes on Inorganic redox reactions
- Part 1 electronegativity, explaining oxidation and reduction reactions and oxidation
state/oxidation number
Revision notes on Inorganic redox reactions
- Part 2 analysing and constructing full
redox equations from half-cell reactions
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Introduction *
Sc * Ti
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Mn
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10c Appendix 8.
Complex ion stability, entropy changes and stability constants (Kstab)
-
Equilibrium expression
for transition metal complex ion formation are readily written out, but
as the case of weak acid ionisation Kc expressions, the
concentration of the solvent water is considered a constant and omitted
from the expression e.g.
-
[Fe(H2O)6]3+(aq) + SCN-(aq) ==> [Fe(H2O)5SCN]2+(aq) + H2O(l)
-
Kstab
= {[Fe(H2O)5SCN]2+(aq)}
/ {[Fe(H2O)6]3+(aq)}
{SCN-(aq)}
= 1.4 x 102 mol-1dm3
-
In this
section {} = concentration, since [] used in complex formulae.
-
The bigger the value of
Kstab the more stable the complex i.e. the equilibrium is more
favoured to the right.
-
Complex formation by
polydentate ligands is sometime called chelation or sequestration.
-
What governs the
values of Kstab?
-
Strength of central
metal ion - ligand bond
-
Substitution with a
bidentate of multidentate ligand leads to more stable complexes.
-
Trend for
a series of
monodentate ligands to do.
-
Comparing mono and
polydentate ligands
-
Why Kstab values
are much higher for polydentate ligands?
-
Consider three Ni(II) complexes:
-
(1)
[Ni(H2O)6]2+(aq) +
6NH3(aq)
[Ni(NH3)6]2+(aq) + 6H2O(l)
-
Kstab
= {[Ni(NH3)6]2+(aq)}
/ {[Ni(H2O)6]2+(aq)}
{EDTA4-(aq)}
-
lg
Kstab is 8.6, a typical value for a complex with a
monodentate ligand (compared to the ligand water) and the Ni-NH3
bonds would appear to be stronger than the Ni-OH2
bonds.
-
(2) bidentate
ligand
-
(3)
[Ni(H2O)6]2+(aq) +
EDTA4-(aq)
[Ni(EDTA)]2-(aq) + 6H2O(l)
-
Kstab
= {[Ni(EDTA)]2-(aq)}
/ {[Ni(H2O)6]2+(aq)}
{EDTA4-(aq)}
-
lg
Kstab is 19.3, considerably higher, EDTA is a
hexadentate ligand
- or even (3)
[Ni(NH3)6]2+(aq) +
EDTA4-(aq)
[Ni(EDTA)]2-(aq) + 6NH3(aq)
-
The Kstab is
much higher for polydentate ligands e.g. reaction
(2), compared to monodentate ligands e.g. reaction (1),
because of the considerable entropy increase in 'freeing' six small
water molecules in reaction (2).
-
In (1) six small molecules
displace six other small molecules, which is likely to involve a much
smaller entropy change.
-
In general the more
water molecules of water freed the greater the entropy increase because
there are more ways of distributing the particles and more ways of
distributing the energy of the system.
-
In general, but with
lots of exceptions!, Kstab values tend to be in the order
polydentate > bidentate > monodentate ligands.
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10c Appendix
9. Colorimetry - quantitative
analysis and determining the formula of a complex ion
-
What is colorimetry?
what is a colorimeter?
-
Colorimetry is
method of determining the concentration of a substance by measuring the
relative absorption of light (usually visible) with respect to a known
concentration of the substance.
-
The instrument by which
these measurements are made is called a colorimeter (illustrated
below).
-

-
Light from a suitable
source is passed through a light filter to select the most
appropriate wavelength of light, some of which is then absorbed by the
solution held in a special glass cuvet (a sort of 'test tube').
-
The amount of light
absorbed is called, and measured as, the absorbance which is a
function of the coloured solute concentration.
-
Most expensive
instruments use a double beam system of two cuvets, one is a 'blank'
of water and one the actual coloured solution under test, two photocells and
sophisticated optics of lenses and mirrors which need not concern as at all.
-
Cheaper colorimeters
(i.e. in school and illustrated above) allow you to put in a cuvet of
'colourless' water, zero the instrument i.e. set it to read zero absorbance,
replace with a cuvet of the coloured solution and simply read of the
'absorbance'. The 'zeroing' is necessary because even the apparently
'colourless blank' of glass cuvet and water can absorbed a tiny amount of
light. This procedure eliminates this error.
-
The filter is chosen
to select the band of wavelengths which are most strongly absorbed by the
coloured solution e.g. this is illustrated on the diagram above, and in
the table below, by using a yellow filter to use in measuring the
concentration of a blue coloured solution like copper(II) sulphate or its
ammine complex.
-
|
The wavelength (nm) of the observed transmitted colour of the solution |
The observed transmitted colour of the solution
(* as
in the diagram above) |
The complementary colour of the
solution i.e. the colour of the filter |
|
400-435 |
violet |
yellowish-green |
|
435-480 * |
blue * |
yellow
* |
|
480-490 |
greenish-blue |
orange |
|
490-500 |
bluish-green |
red |
|
500-560 |
green |
purple |
|
560-580 |
yellowish-green |
violet |
|
580-595 |
yellow |
blue |
|
595-610 |
orange |
greenish-blue |
|
610-750 |
red |
bluish-green |
-
Although the table
illustrates the 'complementary' colour relationship between the solution and
the filter, in practice it is better to try several filters on a typical
concentration of the solution under test to see which filter gives the
highest absorption value i.e. gives you maximum sensitivity and hence
maximum accuracy in your measurements.
-
How do we use
colorimetry to measure the concentration of a transition metal ion?
-
If an aqueous transition
metal ion is intensely coloured, its concentration can be measured directly
e.g. manganese concentration can be measured if it is oxidised to the deep
purple manganate(VII) ion, MnO4-.
-
However, many ions are
not as intense as the MnO4- ion, BUT if a suitable
ligand or complexing agent is added, then a more intensely coloured complex
may be formed, from which accurate measurements of concentration can be made
e.g.
-
The blue
hexaaquacopper(II) ion forms a deeper violet-blue ammine complex with
ammonia.
-
Yellow-brown iron(III)
ions form a deep blood-red complex with the thiocyanate ion (SCN-)
by mixing it with ammonium/potassium cyanate.
-
Once the method of
producing a more intense colour is established, you then need to derive a
calibration curve.
-
This is done by
measuring the absorbance of solutions of known concentrations of the
coloured complex and plotting the calibration curve/graph (see right of
colorimeter diagram).
-
The known concentration
range should include any likely absorbance measured from the solutions under
test i.e. those whose concentration is being determined.
-
Generally at low
concentrations the calibration curve is linear i.e. it obeys Beer's
Law (Beer-Lambert Law). Without going into the mathematics of Beer's Law
and absorption, it basically states that a solution's absorbance is
directly proportional to the concentration of the coloured solute.
-
For various reasons the
calibration may curve upwards (positive deviation from Beer's Law) or curve
over (negative deviation from Beer's Law). However, a linear or otherwise
calibration curve still shows increasing absorption with increasing
concentration and curved calibration graphs are acceptable, if not
advisable, if your methodology is accurate.
-
How can we use
colorimetry to deduce the formula of a complex?
-
The method depends on
measuring the absorbencies of solutions containing different ratios of
transition metal ion to complexing agent.
-
Just for the sake of
argument, imagine that one mole of transition metal (M3+) ion
reacts with two moles of a monodentate ligand (X-). The reaction
equation for the ligand displacement reaction to form the complex would be:
-
There are two basic
approaches as to how you vary the transition metal ion - ligand ratio and
the results illustrated in the diagram below.
-

-
Method (1) The mole
ratio method keeping Mn+ constant and gradually increasing
the number of moles of ligand X from zero to a large molar excess.
-
Method (2) The
continuous variations method in which you start with zero moles of Mn+
and an excess of the ligand X. In each successive mixture you then increase
the amount of Mn+ and decrease the amount of X- and
keep the total moles of Mn+ and X- constant.
-
For the sake of
argument, if you assume both stock solutions are the same molarity,
then the ratio of the volumes automatically gives you the X/M ratio in the
mixture.
-
For the fictitious M3+
and F- complex, the peak will occur between the 6X- :
4M3+ mixture (ratio 1.5) and the 7X- : 3M3+
mixture (ratio 2.33). Theoretically the peak should occur at a ratio of 2.0
for X-/M3+ i.e. theoretically, in terms of a total
volume of 10 units, it means a 6.66X- : 3.33M3+
mixture by volume.
-
For the
iron(III)-thiocyanate complex in reaction (ii) the peak will occur at 5CNS-
: 5Fe3+
-
For the
copper(II)-ammonia complex in reaction (iii) the peak will occur at 8NH3
: 2Cu2+
-
In both cases, you work
out the mole ratios present in the mixtures from the known concentrations
and volumes of the stock solutions of Mn+ and X- used
in each experiment.
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