On-line calculations Quiz 12. Volumetric calculations

Given the neutralisation equation:
NaOH_(aq) + HCl_(aq) ==> NaCl_(aq) + H₂O_(l)
25 cm³ of hydrochloric acid are neutralised by 20 cm³ of 0.05M sodium hydroxide. What is the molarity of the acid? [vct-1]
1. 0.04
2. 0.02
3. 1.25
4. 0.80
Given the neutralisation equation:
NaOH_(aq) + HCl_(aq) ==> NaCl_(aq) + H₂O_(l)
15 cm³ of hydrochloric acid are neutralised by 25 cm³ of 0.06M sodium hydroxide. What is the molarity of the acid? [vct-2]
1. 0.40
2. 0.10
3. 0.04
4. 0.01
Given the neutralisation equation:
NaOH_(aq) + HCl_(aq) ==> NaCl_(aq) + H₂O_(l)
40 cm³ of 0.05M hydrochloric acid are neutralised by 20 cm³ of a sodium hydroxide solution. What is the molarity of the alkali? [vct-3]
1. 0.20
2. 0.05
3. 0.10
4. 0.50
Given the neutralisation equation:
NaOH_(aq) + HCl_(aq) ==> NaCl_(aq) + H₂O_(l)
25 cm³ of 0.16M hydrochloric acid are neutralised by 10 cm³ of a sodium hydroxide solution. What is the molarity of the alkali? [vct-4]
1. 0.2
2. 0.1
3. 0.8
4. 0.4
Given the neutralisation equation:
2KOH_(aq) + H₂SO_4(aq) ==> K₂SO_4(aq) + 2H₂O_(l)
What is the molarity of a sulphuric acid solution, if 15 cm³ of it are neutralised by 20 cm³ of a 0.3 M potassium hydroxide solution? [vct-5]
1. 0.20
2. 0.15
3. 0.40
4. 0.75
Given the neutralisation equation:
2KOH_(aq) + H₂SO_4(aq) ==> K₂SO_4(aq) + 2H₂O_(l)
What is the molarity of a sulphuric acid solution, if 30 cm³ of it are neutralised by 10 cm³ of a 0.6 M potassium hydroxide solution? [vct-6]
1. 0.20
2. 0.10
3. 0.05
4. 0.25
Given the neutralisation equation:
2KOH_(aq) + H₂SO_4(aq) ==> K₂SO_4(aq) +2H₂O_(l)
What is the molarity of a potassium hydroxide solution, if 10 cm³ of it are neutralised by 12 cm³ of a 0.5 M sulphuric acid solution? [vct-7]
1. 2.4
2. 0.6
3. 1.2
4. 0.6
Given the neutralisation equation:
2KOH_(aq) + H₂SO_4(aq) ==> K₂SO_4(aq) + 2H₂O_(l)
What is the molarity of a potassium hydroxide solution, if 5 cm³ of it are neutralised by 20 cm³ of a 1 M sulphuric acid solution? [vct-8]
1. 16
2. 4
3. 5
4. 8
Given the neutralisation equation:
3NaOH_(aq) + H₃PO_4(aq) ==> Na₃PO_4(aq) + 3H₂O_(l)
What is the molarity of a phosphoric acid solution, if 15 cm³ of it are neutralised by 22.5 cm³ of a 0.2 M sodium hydroxide solution? [vct-9]
1. 0.10
2. 0.30
3. 0.03
4. 0.01
Given the neutralisation equation:
3NaOH_(aq) + H₃PO_4(aq) ==> Na₃PO_4(aq) + 3H₂O_(l)
What is the molarity of a phosphoric acid solution, if 40 cm³ of it are neutralised by 15 cm³ of a 0.4 M sodium hydroxide solution? [vct-10]
1. 0.150
2. 0.050
3. 0.017
4. 0.115
Given the neutralisation equation:
3NaOH_(aq) + H₃PO_4(aq) ==> Na₃PO_4(aq) + 3H₂O_(l)
What is the molarity of a sodium hydroxide solution, if 21.6 cm³ of it are neutralised by 18 cm³ of a 0.2 M phosphoric acid solution? [vct-11]
1. 1.50
2. 1.15
3. 0.50
4. 0.17
Given the neutralisation equation:
3NaOH_(aq) + H₃PO_4(aq) ==> Na₃PO_4(aq) + 3H₂O_(l)
What is the molarity of a sodium hydroxide solution, if 15 cm³ of it are neutralised by 20 cm³ of a 0.6 M phosphoric acid solution? [vct-12]
1. 1.2
2. 7.2
3. 0.8
4. 2.4

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On-line calculations Quiz 12. Volumetric calculations - titrations

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