Given the reaction between hydrogen and chlorine to form hydrogen chloride: H2(g) + Cl2(g) ==> 2HCl(g) What volume of hydrogen in cm3 is needed to make 100cm3 of hydrogen chloride? [rgv-1]
Given the reaction between hydrogen and chlorine to form hydrogen chloride: H2(g) + Cl2(g) ==> 2HCl(g) What volume of chlorine in dm3 is needed to make 40dm3 of hydrogen chloride? [rgv-2]
Given the reaction between hydrogen and chlorine to form hydrogen chloride: H2(g) + Cl2(g) ==> 2HCl(g) What volume of hydrogen chloride in dm3 is made by reacting 20dm3 of hydrogen? [rgv-3]
Given the reaction between hydrogen and chlorine to form hydrogen chloride: H2(g) + Cl2(g) ==> 2HCl(g) What volume of hydrogen chloride in cm3 is made by reacting 300cm3 of chlorine? [rgv-4]
Given the reaction between nitrogen and hydrogen to form ammonia: N2(g) + 3H2(g) ==> 2NH3(g) What volume of ammonia in cm3 is formed if 180cm3 of hydrogen reacts? [rgv-5]
Given the reaction between nitrogen and hydrogen to form ammonia: N2(g) + 3H2(g) ==> 2NH3(g) What volume of ammonia in dm3 is formed if 40dm3 of nitrogen reacts? [rgv-6]
Given the reaction between nitrogen and hydrogen to form ammonia: N2(g) + 3H2(g) ==> 2NH3(g) What volume of hydrogen in dm3 is needed to make 60dm3 of ammonia? [rgv-7]
Given the reaction between nitrogen and hydrogen to form ammonia: N2(g) + 3H2(g) ==> 2NH3(g) What volume of nitrogen in cm3 is needed to make 640cm3 of ammonia? [rgv-8]
The combustion of methane is given by the equation: CH4(g) + 2O2(g) ==> CO2(g) + 2H2O(l) What volume of oxygen in cm3 is needed to burn 200cm3 of methane? [rgv-9]
The combustion of methane is given by the equation: CH4(g) + 2O2(g) ==> CO2(g) + 2H2O(l) What volume of carbon dioxide in cm3 is formed on burning 10cm3 of methane? [rgv-10]
The combustion of methane is given by the equation: CH4(g) + 2O2(g) ==> CO2(g) + 2H2O(g) What is the total volume of gases produced in cm3 when 30cm3 of methane burns? [rgv-11]
The combustion of propane is given by the equation: C3H8(g) + 5O2(g) ==> 3CO2(g) + 4H2O(l) What volume of oxygen in cm3 is needed to burn 20cm3 of propane? [rgv-12]
The combustion of propane is given by the equation: C3H8(g) + 5O2(g) ==> 3CO2(g) + 4H2O(l) What volume of propane in cm3 can be completely burned by 200cm3 of oxygen? [rgv-13]
The combustion of propane is given by the equation: C3H8(g) + 5O2(g) ==> 3CO2(g) + 4H2O(l) What volume of carbon dioxide in dm3 is formed by burning 30dm3 of propane? [rgv-14]
The combustion of propane is given by the equation: C3H8(g) + 5O2(g) ==> 3CO2(g) + 4H2O(g) What total volume of gases in cm3 is formed by burning 40cm3 of propane? [rgv-15]
The combustion of propane is given by the equation: C3H8(g) + 5O2(g) ==> 3CO2(g) + 4H2O(g) What volume of steam in cm3 is formed by burning 20cm3 of propane? [rgv-16]
The combustion of ethane is given by the equation: 2C2H6(g) + 7O2(g) ==> 4CO2(g) + 6H2O(l) What volume of carbon dioxide in cm3 is formed by burning 20cm3 of ethane? [rgv-17]
The combustion of ethane is given by the equation: 2C2H6(g) + 7O2(g) ==> 4CO2(g) + 6H2O(l) What volume of oxygen in cm3 is needed to completely burn 60cm3 of ethane? [rgv-18]
The combustion of ethane is given by the equation: 2C2H6(g) + 7O2(g) ==> 4CO2(g) + 6H2O(g) What volume of steam in dm3 is formed when 40dm3 of ethane burns? [rgv-19]
The combustion of ethane is given by the equation: 2C2H6(g) + 7O2(g) ==> 4CO2(g) + 6H2O(g) What total volume of gases in dm3 are formed when 15dm3 of ethane burns? [rgv-20]
The combustion of ethane is given by the equation: 2C2H6(g) + 7O2(g) ==> 4CO2(g) + 6H2O(g) What volume of ethane in cm3 can be burned completely using 175cm3 of oxygen? [rgv-21]
A cracking reaction to break down a large hydrocarbon molecule into, in order, hexane, propene and ethene, is shown below. C18H38(g) ==> C6H14(g) + 2C3H6(g) + 3C2H4(g) What total volume in dm3 of hydrocarbon gases are formed when 20dm3 of the large hydrocarbon are broken down? [rgv-22]
A cracking reaction to break down a large hydrocarbon molecule into, in order, hexane, propene and ethene, is shown below. C18H38(g) ==> C6H14(g) + 2C3H6(g) + 3C2H4(g) What volume in cm3 of propene gas is formed when 120cm3 of the large hydrocarbon are broken down? [rgv-23]
A cracking reaction to break down a large hydrocarbon molecule into, in order, hexane, propene and ethene, is shown below. C18H38(g) ==> C6H14(g) + 2C3H6(g) + 3C2H4(g) What volume in cm3 of ethene gas is formed when 40cm3 of the large hydrocarbon are broken down? [rgv-24]
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