On-line Calculations Quiz 3. "Law of conservation of mass"

Given the following symbol equation:
2Mg + O₂ ==> 2MgO
Calculate how many g of magnesium oxide is formed by burning 24g of magnesium in air.
(Relative atomic masses, A_r: Mg = 24 and O = 16) [com-1]
Given the following symbol equation:
2Mg + O₂ ==> 2MgO
Calculate how many tonne of magnesium is needed to make 80 tonne of magnesium oxide.
(Relative atomic masses, A_r: Mg = 24 and O = 16) [com-2]
Given the following symbol equation:
CaCO_3(s) ==> CaO_(s) + CO_2(g)
Calculate how many kg of calcium carbonate is needed to make 56 kg of calcium oxide.
(Relative atomic masses, A_r: Ca = 40, C = 12 and O = 16) [com-3]
Given the following symbol equation:
CaCO_3(s) ==> CaO_(s) + CO_2(g)
Calculate how many g of carbon dioxide is formed if 25g of calcium carbonate is decomposed on heating to form 14g of calcium oxide.
(Relative atomic masses, A_r: Ca = 40, C = 12 and O = 16) [com-4]
Given the symbol equation to show the formation of iron sulphide:
Fe + S ==> FeS
Calculate the mass in g of iron sulphide formed when 5.6g of iron combines with 3.2g of sulphur.
(Relative atomic masses, A_r: Fe = 56 and S = 32) [com-5]
Given the symbol equation to show the formation of iron sulphide:
Fe + S ==> FeS
Calculate the mass in g of iron sulphide formed when 28g of iron combines with 16g of sulphur.
(Relative atomic masses, A_r: Fe = 56 and S = 32) [com-6]
Given the symbol equation to show the formation of calcium chloride by burning calcium in chlorine:
Ca_(s) + Cl_2(g) ==> CaCl_2(s)
Calculate the mass in g of calcium chloride formed when 20g of calcium combines with 35.5g of chlorine.
(Relative atomic masses, A_r: Ca = 40 and Cl = 35.5) [com-7]
Given the symbol equation to show the formation of calcium chloride by burning calcium in chlorine:
Ca_(s) + Cl_2(g) ==> CaCl_2(s)
Calculate the mass in g of chlorine needed when 40g of calcium forms 111g of calcium chloride.
(Relative atomic masses, A_r: Ca = 40 and Cl = 35.5) [com-8]
Given the symbol equation to show the formation of aluminium sulphide by heating a mixture of aluminium and sulphur:
2Al + 3S ==> Al₂S₃
How many g of sulphur is needed if 54g of aluminium is reacted to form 150g of aluminium sulphide?
(Relative atomic masses, A_r: Al = 27 and S = 32) [com-9]
Given the symbol equation to show the formation of aluminium sulphide by heating a mixture of aluminium and sulphur:
2Al + 3S ==> Al₂S₃
How many kg of sulphur is needed if 108kg of aluminium is reacted to form 300kg of aluminium sulphide?
(Relative atomic masses, A_r: Al = 27 and S = 32) [com-10]
Given the symbol equation to show the formation of iron sulphide by heating a mixture of iron and sulphur:
Fe + S ==> FeS
Calculate the mass in g of iron unreacted when 60g of iron reacts with 32g of sulphur to form 88g of iron sulphide.
(Relative atomic masses, A_r: Fe = 56 and S = 32) [com-11]
Given the symbol equation to show the formation of iron sulphide by heating a mixture of iron and sulphur:
Fe + S ==> FeS
Calculate the mass in g of sulphur unreacted when 28g of iron reacts with 22g of sulphur to form 44g of iron sulphide.
(Relative atomic masses, A_r: Fe = 56 and S = 32) [com-12]
Given the symbol equation to show the formation of calcium chloride by burning calcium in chlorine:
Ca_(s) + Cl_2(g) ==> CaCl_2(s)
Calculate the mass in g of calcium left unreacted when 25g of calcium reacts with 35.5g of chlorine.
(Relative atomic masses, A_r: Ca = 40 and Cl = 35.5) [com-13]
Given the symbol equation to show the formation of calcium chloride by burning calcium in chlorine:
Ca_(s) + Cl_2(g) ==> CaCl_2(s)
Calculate the mass in g of chlorine left unreacted when 80g of calcium reacts with 150g of chlorine to form 222g of calcium chloride.
(Relative atomic masses, A_r: Ca = 40 and Cl = 35.5) [com-14]

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On-line Calculations Quiz 3. "Law of conservation of mass"

Type in an answer and click CHECK, no need for units, lower case only. All GCSE Chemistry, Earth Science and Radioactivity Quizzes"Doc Brown's Chemistry Clinic" EMAIL query?comment, quote Q ref [com-xx]) (01-06-09)