GCSE/IGCSE/AS Chemistry Online Calculation Questions Quiz 3. Law of conservation of mass

Given the following symbol equation:
2Mg + O₂ ==> 2MgO
Calculate how many g of magnesium oxide is formed by burning 24g of magnesium in air.
(Relative atomic masses, A_r: Mg = 24 and O = 16) [com-1]
1. 40
2. 16
3. 20
4. 80
Given the following symbol equation:
2Mg + O₂ ==> 2MgO
Calculate how many tonne of magnesium is needed to make 80 tonne of magnesium oxide.
(Relative atomic masses, A_r: Mg = 24 and O = 16) [com-2]
1. 96
2. 48
3. 24
4. 16
Given the following symbol equation:
CaCO_3(s) ==> CaO_(s) + CO_2(g)
Calculate how many kg of calcium carbonate is needed to make 56 kg of calcium oxide.
(Relative atomic masses, A_r: Ca = 40, C = 12 and O = 16) [com-3]
1. 50
2. 44
3. 100
4. 40
Given the following symbol equation:
CaCO_3(s) ==> CaO_(s) + CO_2(g)
Calculate how many g of carbon dioxide is formed if 25g of calcium carbonate is decomposed on heating to form 14g of calcium oxide.
(Relative atomic masses, A_r: Ca = 40, C = 12 and O = 16) [com-4]
1. 22
2. 44
3. 10
4. 11
Given the symbol equation to show the formation of iron sulphide:
Fe + S ==> FeS
Calculate the mass in g of iron sulphide formed when 5.6g of iron combines with 3.2g of sulphur.
(Relative atomic masses, A_r: Fe = 56 and S = 32) [com-5]
1. 8.8
2. 2.4
3. 5.6
4. 3.2
Given the symbol equation to show the formation of iron sulphide:
Fe + S ==> FeS
Calculate the mass in g of iron sulphide formed when 28g of iron combines with 16g of sulphur.
(Relative atomic masses, A_r: Fe = 56 and S = 32) [com-6]
1. 12
2. 44
3. 28
4. 16
Given the symbol equation to show the formation of calcium chloride by burning calcium in chlorine:
Ca_(s) + Cl_2(g) ==> CaCl_2(s)
Calculate the mass in g of calcium chloride formed when 20g of calcium combines with 35.5g of chlorine.
(Relative atomic masses, A_r: Ca = 40 and Cl = 35.5) [com-7]
1. 15.5
2. 70.0
3. 55.5
4. 17.5
Given the symbol equation to show the formation of calcium chloride by burning calcium in chlorine:
Ca_(s) + Cl_2(g) ==> CaCl_2(s)
Calculate the mass in g of chlorine needed when 40g of calcium forms 111g of calcium chloride.
(Relative atomic masses, A_r: Ca = 40 and Cl = 35.5) [com-8]
1. 80
2. 100
3. 151
4. 71
Given the symbol equation to show the formation of aluminium sulphide by heating a mixture of aluminium and sulphur:
2Al + 3S ==> Al₂S₃
How many g of sulphur is needed if 54g of aluminium is reacted to form 150g of aluminium sulphide?
(Relative atomic masses, A_r: Al = 27 and S = 32) [com-9]
1. 96
2. 204
3. 64
4. 27
Given the symbol equation to show the formation of aluminium sulphide by heating a mixture of aluminium and sulphur:
2Al + 3S ==> Al₂S₃
How many kg of sulphur is needed if 108kg of aluminium is reacted to form 300kg of aluminium sulphide?
(Relative atomic masses, A_r: Al = 27 and S = 32) [com-10]
1. 408
2. 192
3. 96
4. 32
Given the symbol equation to show the formation of iron sulphide by heating a mixture of iron and sulphur:
Fe + S ==> FeS
Calculate the mass in g of iron unreacted when 60g of iron reacts with 32g of sulphur to form 88g of iron sulphide.
(Relative atomic masses, A_r: Fe = 56 and S = 32) [com-11]
1. 8
2. 32
3. 4
4. 56
Given the symbol equation to show the formation of iron sulphide by heating a mixture of iron and sulphur:
Fe + S ==> FeS
Calculate the mass in g of sulphur unreacted when 28g of iron reacts with 22g of sulphur to form 44g of iron sulphide.
(Relative atomic masses, A_r: Fe = 56 and S = 32) [com-12]
1. 22
2. 16
3. 12
4. 6
Given the symbol equation to show the formation of calcium chloride by burning calcium in chlorine:
Ca_(s) + Cl_2(g) ==> CaCl_2(s)
Calculate the mass in g of calcium left unreacted when 25g of calcium reacts with 35.5g of chlorine.
(Relative atomic masses, A_r: Ca = 40 and Cl = 35.5) [com-13]
1. 10.5
2. 5.0
3. 7.1
4. 12.5
Given the symbol equation to show the formation of calcium chloride by burning calcium in chlorine:
Ca_(s) + Cl_2(g) ==> CaCl_2(s)
Calculate the mass in g of chlorine left unreacted when 80g of calcium reacts with 150g of chlorine to form 222g of calcium chloride.
(Relative atomic masses, A_r: Ca = 40 and Cl = 35.5) [com-14]
1. 70
2. 8
3. 16
4. 72

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GCSE/IGCSE/AS Chemistry Online Calculation Questions Quiz 3. Law of conservation of mass

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